2 years ago

Find f'(x) for the given function. f(x)=1/8+x

Mathematics

1 answer:

Novay_Z [31]2 years ago

3 0

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Jill earns 1.5 times her normal hourly rate for each hour she works after 40 hours in a week. she worked 52 hours this week and

beks73 [17]

This equation can be set up letting x be the hourly rate:40x+1.5x(52-40)=638 [40 times the rate, plus 1.5 times the rate for the hours over 40 equals the pay]40x+78x-60x=63858x=638x=11 hourly rate is $11/hr

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3 years ago

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The temperature at a ski resort was 12°F at 5:00 A.M. If the temperature increased by 1.5°F each hour, what would be the tempera

Mariana [72]

The correct answer is:

22.5° F.

Explanation:

The temperature increases 1.5° per hour. From 5:00 AM to 12:00 PM is 12-5 = 7 hours. This makes an increase of 1.5(7) = 10.5°.

The temperature started at 12°F; increasing by 10.5° gives us

12+10.5 = 22.5°F.

3 0

2 years ago

Complete the pattern: 6,7, 12, 13, 18, Next two numbers

jeka94

Answer:

19, 24

Step-by-step explanation:

the pattern adds one then adds five

+1, +5, +1, +5, on and on

6+1 is 7

7+5 is 12

12+1 is 13

13+5 is 18

18+1 is 19

19+5 is 24

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3 years ago

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In trapezoid PQRS, identify PQ.

larisa86 [58]

The answer will be 35 because it is a proportional side length

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1 year ago

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Evaluate tan45/sin30 . In your final answer, include all calculations.

Maslowich

From the identity $\displaystyle{ \tan x= \frac{\sin x}{\cos x}$ , and from the values:

$\sin45^{\circ}=\cos45^{\circ}= \frac{ \sqrt{2}}{2}$ ,

we have: $\displaystyle{ \tan 45^{\circ}= \frac{\sin 45^{\circ}}{\cos 45^{\circ}}= \frac{ \frac{ \sqrt{2}}{2}}{\frac{ \sqrt{2}}{2}} =1$ .

We also know that $\sin30^{\circ}= \frac{1}{2}$ .

Thus, $\displaystyle{ \frac{\tan 45^{\circ}}{\sin30^{\circ}} = \frac{1}{\frac{1}{2}}=2.$

Answer: 2

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3 years ago