F (a)=2a^2-16a+32 For which 'a' is this equation 0?

1 answer:

7 0

If xy=0 assume that at leas 1 is zero
set it to zero

0=2a^2-16a+32
undistribute 2
0=2(a^2-8a+16)
2*0=0 so assume
a^2-8a+16=0
factor
(a-4)(a-4)=0
set to zero
a-4=0
a=4

when a=4, equation equals zero

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