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Arte-miy333 [17]
3 years ago
14

What is the location of the point on the number line that is 2/5 of the way from A = -6 to B = 9

Mathematics
1 answer:
sammy [17]3 years ago
5 0
The distance between is =|9|+|-6|=15.
We can find that
\frac{2}{5}  \times 15 = 6
So 2/5 of the AB segment is 6 distance points away from A at point C=0.

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Please help me on this <br> U need to zoom in
rodikova [14]
Not sure if you can do this but it sounds like a velocity/time/distance equation.
d=vt
v=d/t
t=d/v

70 w/m = t
15 pages - 350 w/p

She can type 70 words per minute (w/m). There are 350 words per page (w/p). She needs 15 pages. So first you have to find how many words she can type in one hour. 60 minutes in an hour, she can type 70 w/p.

60x70=4,200 words per hour (w/h).

Next you should find out how many words on 15 pages total.
350x15= 5,250.

I would put 4,200/5,250 as a fraction to gage how much she has left. She has most of it done already in ONE HOUR. Reduced, she has done 4/5s of the essay. Now you just need to get 1/5 of 5250, which is 1050.

She needs to do 1050 words. If one minute is 70, do 1050/70 which is 15.

The answer is 1 hour and 15 minutes.

I think... ;)
3 0
3 years ago
I need help with these as well
Mkey [24]
The answer to c. Is 8t+12g
4 0
3 years ago
What is a b c in 3x^2+4=5x
____ [38]

Answer:

a =3

b = -5

c = 4

Step-by-step explanation:

3x^2+4=5x

Subtract 5x from each side

3x^2-5x+4=5x-5x

3x^2-5x+4=0

The equation is in the form

ax^2 +bx+c =0

a =3

b = -5

c = 4

5 0
3 years ago
Find a point-slope form for the line with slope 1/5 and passing through the point (-4,-9).
sattari [20]

Answer:

y + 9 = \frac{1}{5}(x + 4)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = \frac{1}{5} and (a, b) = (- 4, - 9) , thus

y - (- 9) = \frac{1}{5}(x - (- 4) ) , that is

y + 9 = \frac{1}{5}(x + 4)

3 0
2 years ago
If f(x-3)=x^2-4x+5, what's f(1-x)​
olganol [36]

Answer:

\large\boxed{f(1-x)=x^2-4x+5}

Step-by-step explanation:

f(x-3)=x^2-4x+5\\\\f((x-3)+3)\to\text{put x + 3 to the equation of the function:}\\\\f(x-3+3)=(x+3)^2-4(x+3)+5\\\text{use the distributive property and}\ (a+b)^2=a^2+2ab+b^2\\f(x)=x^2+2(x)(3)+3^2+(-4)(x)+(-4)(3)+5\\f(x)=x^2+6x+9-4x-12+5\qquad\text{combine like terms}\\f(x)=x^2+(6x-4x)+(9-12+5)\\f(x)=x^2+2x+2\\\\f(1-x)\to\text{put 1 - x to the equation of the funtion f(x):}\\\\f(1-x)=(1-x)^2+2(1-x)+2\\\text{use the distributive property and}\ (a-b)^2=a^2-2ab+b^2

f(1-x)=1^2-2(1)(x)+x^2+(2)(1)+(2)(-x)+2\\f(1-x)=1-2x+x^2+2-2x+2\qquad\text{combine like terms}\\f(1-x)=x^2+(-2x-2x)+(1+2+2)\\f(1-x)=x^2-4x+5

4 0
3 years ago
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