Answer:
Step-by-step explanation:
Use the point-slope formula by the line
y - y_1 = m(x - x_1) when x_1 =8 and y_1 = -2 m : is the slope (same slope for the line whose equation is 3x + 4y = 15 because are parallel)
calculate : m
3x + 4y = 15
4y = -3x +15
y = (-3/4)x +15/4 so m = -3/4
an equation is : y +2 =(-3/4)(x-8)
Here, we know 1/100 = 0.01
Now, question has reduced to 0.01 vs 0.1
We can easily see 0.1 is greater.
In short, Your Answer would be 0.1 is bigger
Hope this helps!
18. Solve for x by factoring diamond method
10x^2 - 29x - 21 = 0 becomes
(2x - 7)(5x + 3) = 0
x = 7/2, -3/5
A
19. To model this we will do
(x + 9)(x + 9) = 169
distribute
x^2 + 18x - 88 = 0
factor
(x - 4)(x + 22) = 0
The length is 4m
D
20. This can be modeled by
(l)(l +5) = 234
distribute
l^2 + 5l -234 = 0
factor
(l-13)(l+18) = 0
The length is 13
The width is 18
B
21. To find this you divide the x term by 2 and square it so
10/2 = 5
5^2
25
B
22. To find this you divide the x term by 2 and square it so
9/2 = 4.5
4.5^2
81/4
C
To multiply two polynomials, multiply every term of the first polynomial by every term of the second polynomial. Then combine like terms.
I like to take the each term of the first polynomial and multiply by every term of the second polynomial.
<span>(y^2 + 3y + 7)(8y^2 + y + 1) =
= y^2 * 8y^2 + y^2 * y + y^2 * 1 + 3y * 8y^2 + 3y * y + 3y * 1 + 7 * 8y^2
+ 7 * y + 7 * 1 <-------- first step of solution
= 8y^4 + y^3 + y^2 + 24y^3 + 3y^2 + 3y + 56y^2 + 7y + 7 <--- notice 9 terms
= 8y^4 + 25y^3 + 60y^2 + 10y + 7
Notes:
1) I usually don't write the first step of my solution. I wrote it here to show you all the multiplications of terms that need to be done.
2) As a check, make sure the number of products of terms equals the product of the numbers of terms of the two polynomials. These polynomials have 3 terms each. 3 * 3 = 9, and sure enough, there are 9 products in the first step of the solution.
</span>
Step-by-step explanation:
the answer is 10x - 8.
3x+2
5x-7
2x-3
--------
10x-8
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-------- hope this helps you and please try to mark me as BRAINLIST.