first yo need to find a price of camera. then you can find a price of laptop.
Answer:
![\chi^2 = \frac{(83-90)^2}{90} +\frac{(68-72)^2}{72}+\frac{(85-78)^2}{78}+\frac{(64-60)^2}{60} = 1.66](https://tex.z-dn.net/?f=%5Cchi%5E2%20%3D%20%5Cfrac%7B%2883-90%29%5E2%7D%7B90%7D%20%2B%5Cfrac%7B%2868-72%29%5E2%7D%7B72%7D%2B%5Cfrac%7B%2885-78%29%5E2%7D%7B78%7D%2B%5Cfrac%7B%2864-60%29%5E2%7D%7B60%7D%20%3D%201.66)
And the answer would be:
c. 1.66
Step-by-step explanation:
We need to conduct a chi square test
The statistic to check the hypothesis is given by:
the observed values for this case are:
![Freshemen=83](https://tex.z-dn.net/?f=%20Freshemen%3D83)
![Sophomores=68](https://tex.z-dn.net/?f=%20Sophomores%3D68)
![Juniors = 85](https://tex.z-dn.net/?f=%20Juniors%20%3D%2085)
![Seniors= 64](https://tex.z-dn.net/?f=Seniors%3D%2064)
The expected values for this case are:
![Fres_E =0.3*300= 90](https://tex.z-dn.net/?f=%20Fres_E%20%3D0.3%2A300%3D%2090)
![Sop_E =0.24*300= 72](https://tex.z-dn.net/?f=%20Sop_E%20%3D0.24%2A300%3D%2072)
![Jun_E = 0.26*300 =78](https://tex.z-dn.net/?f=Jun_E%20%3D%200.26%2A300%20%3D78)
![Sen_E = 0.20*300= 60](https://tex.z-dn.net/?f=%20Sen_E%20%3D%200.20%2A300%3D%2060)
Then the statistic would be given by:
![\chi^2 = \frac{(83-90)^2}{90} +\frac{(68-72)^2}{72}+\frac{(85-78)^2}{78}+\frac{(64-60)^2}{60} = 1.66](https://tex.z-dn.net/?f=%5Cchi%5E2%20%3D%20%5Cfrac%7B%2883-90%29%5E2%7D%7B90%7D%20%2B%5Cfrac%7B%2868-72%29%5E2%7D%7B72%7D%2B%5Cfrac%7B%2885-78%29%5E2%7D%7B78%7D%2B%5Cfrac%7B%2864-60%29%5E2%7D%7B60%7D%20%3D%201.66)
And the answer would be:
c. 1.66
Answer:
C
27g=x miles on a full tank of gas
27(16)=x
x=432 miles
Step-by-step explanation:
- $3.20x18.5=$59.20
- 18.5-2.5=16 gallons
- 16 gallons x 27 miles= 432 miles
- 27g=x miles on a full tank of gas
- 27(16)=x
- x=432 miles
Answer:
± 2
Step-by-step explanation:
let the number be n , then
n² - 4 = 0 ( add 4 to both sides )
n² = 4 ( take square root of both sides )
n = ±
= ± 2
The number is - 2 or 2