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3 years ago

Which linear inequality is represented by the graph?

Mathematics

1 answer:

jarptica [38.1K]3 years ago

6 0

Answer: y > 2x + 1

Step-by-step explanation:

In the graph first, we can see two things:

The line is not solid (so the values in the line are not included), and the shaded part is above, so we will be using the symbol:

y > f(x)

Now, in the line we can see that when x = 0, y = 1.

So the linear equation must be something like:

f(x) = a*x + 1

The only one that has an y-intercept equal to 1 is y > 2x + 1

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In the figure above line m is parallel to line n.

enot [183]

Given:

Line m is parallel to line n.

The measure of ∠1 is (4x + 15)°

The measure of ∠2 is (9x + 35)°

We need to determine the measure of ∠1

Value of x:

From the figure, it is obvious that ∠1 and ∠2 are linear pairs.

Thus, we have;

$\angle 1+\angle 2=180^{\circ}$

Substituting the measures of ∠1 and ∠2, we get;

$4x+15+9x+35=180$

$13x+50=180$

$13x=130$

$x=10$

Thus, the value of x is 10.

Measure of ∠1:

The measure of ∠1 can be determined by substituting x = 10 in the measure of ∠1

Thus, we have;

$\angle 1 =4(10)+15$

$=40+15$

$\angle 1=55^{\circ}$

Thus, the measure of ∠1 is 55°

7 0

3 years ago

Help please!!! What is P(0.6 ≤ z ≤ 2.12)? 16% 26% 73% 98%

Lelu [443]

26% is the answer to your question

5 0

3 years ago

Read 2 more answers

You are planning to make an open rectangular box from aa 4141-in.-by-8181-in. piece of cardboard by cutting congruent squares

marissa [1.9K]

Answer:

13058.83 cubic inches

Step-by-step explanation:

Given that a rectangular box is having dimensions as 41x81 inches.

Let x be the side of square cut from all the four corners.

The open box made would have height as x and length 41-2x with width 81-2x

Volume =

$V(x) = x(41-2x)(81-2x)\\V(x) =x(3321-244x+4x^2)\\V(x) = 3321x-244x^2+4x^3\\V'(x) = 3321-488x+12x^2\\V"(x) = -488+24x\\$

Equate first derivative to 0

We get applicable root as x = 8.642

Max volume = 13058.83 cubic inches

3 0

3 years ago

Somebody help plz how can i solve the following equations of 6v+3=21

IrinaK [193]

21-3= 18 and 18 divided by 6 equals 3 so v=3

6 0

3 years ago

For what value of k will these pairs of simultaneous equations have no solution?

yKpoI14uk [10]

Kx-3y=k
y=4x+1 ( we will put it in 1st equation )
kx - 3 (4x+1)=k
kx - 12 x - 3 =k
kx - 12 x = k+3
x(k-12) = k+3
x= $\frac{k+3}{k-12}$
Also y= $\frac{5k}{k-12}$
We can not divide with zero.
k-12=0
k=12
For k= 12 equations have no solutions.

4 0

3 years ago