Answer: 3.675 seconds
Step-by-step explanation:
Hi, when the object hits the ground, h=0:
h=−16t^2+48.6t+37.5
0=−16t^2+48.6t+37.5
We have to apply the quadratic formula:
For: ax2+ bx + c
x =[ -b ± √b²-4ac] /2a
Replacing with the values given:
a=-16 ; b=48.6; c=37.5
x =[ -(48.6) ± √(-48.6)²-4(-16)37.5] /2(-16)
x = [ -48.6 ± √ 4,761.96] /-32
x = [ -48.6 ± 69] /-32
Positive:
x = [ -48.6 + 69] /-32 = -0.6375
Negative:
x = [ -48.6 - 69] /-32 = 3.675 seconds (seconds can't be negative)
Feel free to ask for more if needed or if you did not understand something.
Answer: 6767/10000
Step-by-step explanation:
Just simplify it by its nearest tenth
Answer:
As shown in picture, this is a trapezoid.
The area of a trapezoid is calculated by:
A = (base1 + base2) x height x (1/2)
To work out A, we need to find out base1, base2, and height.
base1 = YZ = 
base2 = XW =
Otherwise, the height (distance between base1 and base2) is 4 as shown in picture.
=> A = (3 + 7) x 4 x (1/2) = 20
Hope this helps!
:)
Answer:
3
Step-by-step explanation:
Answer: (12) ∠1 = 20° (13) ∠2 = 50° (14) ∠3 = 15° (15) UV = 80° (16) AB = 40° (17) ABC <em>or</em> 180° - CD (18) BC - 140° (19) ABC = 150°
<u>Step-by-step explanation:</u>
12)
(UV - ST) = ∠1
(80 - 40) = ∠1
(40) = ∠1
20 = ∠1
13)
(UV + ST) = ∠2
(70 + 30) = ∠2
(100) = ∠2
50 = ∠2
14)
(VB - BS) = ∠3
(60 - 30) = ∠3
(30) = ∠3
15 = ∠3
15)
(UV - ST) = ∠1
(UV - 20) = 30
UV - 20 = 60
UV = 80
16) ∠1 = arc AB
∠1 = 40
arc AB = 40
17) arc AB + arc BC = arc AC
= 180 = arc CD
18) ∠1 + ∠2 + ∠3 = 180
20 + ∠2 + 20 = 180
∠2 + 40 = 180
∠2 = 140
19) ∠1 + ∠ 2 = arc ABC
∠1 + ∠2 + ∠3 = 180
arc ABC + 30 = 180
arc ABC = 150