At the Olympic games, many events have several rounds of competition. One of these events is the men's 100100100-meter backstrok
e.
The upper dot plot shows the times (in seconds) of the top 888 finishers in the final round of the 201220122012 Olympics. The lower dot plot shows the times of the same 888 swimmers, but in the semifinal round.
Which pieces of information can be gathered from these dot plots? (Remember that lower swim times are faster.)
The upper dot plot shows the times (in seconds) of the top 888 finishers in the final round of the 201220122012 Olympics. The lower dot plot shows the times of the same 888 swimmers, but in the semifinal round.
Which pieces of information can be gathered from these dot plots? (Remember that lower swim times are faster.)
1 answer:
You might be interested in
we have
Step 1
Applying the distributive property in the left side ( Multiply the factors on the left side)
therefore
<u>the answer is</u>
Answer:
Step-by-step explanation:
Given that a researcher is trying to decide how many people to survey.
We have confidence intervals are intervals with middle value as the mean and on either side margin of error.
Confidence interval = Mean ± Margin of error
Thus confidence interval width depends on margin of error.
Margin of error =
Thus for the same confidence level and std deviation we find margin of error is inversely proportional to square root of sample size.
Hence for small n we get wide intervals.
So if sample size = 300, the researcher will get wider confidence interval
Equate whats inside (arguments) with base period of sine function
and solve for x to get period,
So the period of the graph of the given function is precisely 2.
Hope this helps :)