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anastassius [24]
3 years ago
15

At the Olympic games, many events have several rounds of competition. One of these events is the men's 100100100-meter backstrok

e.
The upper dot plot shows the times (in seconds) of the top 888 finishers in the final round of the 201220122012 Olympics. The lower dot plot shows the times of the same 888 swimmers, but in the semifinal round.


Which pieces of information can be gathered from these dot plots? (Remember that lower swim times are faster.)

Mathematics
1 answer:
padilas [110]3 years ago
8 0

Answer:

C

Step-by-step explanation:

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Step-by-step explanation:

(3x + 10) + (5x + 18) = 180 \\ 8x + 28 = 180 \\ 8x = 152 \\ x =  \frac{152}{8}  \\ x = 19

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Math!! Who knows answers???
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option C for Qno10

and option a for Qno 9

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Choose the equation of the vertical line passing through the point (−4, 2).
Degger [83]
Vertical line has no slope. so only look at the x value. x=-4.
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The ratio of two numbers is 2/3. The sum of the numbers is 105. What are the two numbers?
Pepsi [2]
A) x/y = 2/3
B) x + y = 105
Solving Equation A for y
A) y = 1.5x
Substituting A into B
B) x + 1.5x = 105
2.5x = 105
x = 42
y = 63


8 0
3 years ago
Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
likoan [24]

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=15,\:\quad a_n=2

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5

=\left(x+3\right)\left(2x^2-11x+5\right)

Factor: 2x^2-11x+5

2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)

=x\left(2x-1\right)-5\left(2x-1\right)

2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)

\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:}

thus zeros of f(x) is

x=-3,\:x=5,\:x=\frac{1}{2}

5 0
2 years ago
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