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Leto [7]
3 years ago
5

Guys help please I am struggling

Mathematics
1 answer:
alina1380 [7]3 years ago
8 0

9514 1404 393

Answer:

  14.1 years

Step-by-step explanation:

Use the compound interest formula and solve for t. Logarithms are involved.

  A = P(1 +r/n)^(nt)

amount when P is invested for t years at annual rate r compounded n times per year.

Using the given values, we have ...

  13060 = 8800(1 +0.028/365)^(365t)

  13060/8800 = (1 +0.028/365)^(365t) . . . . divide by P=8800

Now we take logarithms to make this a linear equation.

  log(13060/8800) = (365t)log(1 +0.028/365)

Dividing by the coefficient of t gives us ...

  t = log(13060/8800)/(365·log(1 +0.028/365)) ≈ 0.171461/0.0121598

  t ≈ 14.1

It would take about 14.1 years for the value to reach $13,060.

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Opal wanted to make some necklaces and sell them at a craft store. She made 37 necklaces and each necklace had somewhere between
alexandr402 [8]
<h3>The total number of beads used in making 37 necklaces is between 2,664 beads and 2,849 beads.</h3>

Step-by-step explanation:

Here, as given: The number of necklace made by Opal  = 37

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So, the least number of total beads used in 37 necklaces  = 2,664 beads

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So, if highest number of total beads used in 37 necklaces  = 2,849 beads

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5 0
3 years ago
For the vectors u and v with magnitudes u = 88 and v = 99​, find the angle θ between u and v which makes u and v = 77.
WARRIOR [948]

Answer:

<h2>89.5°</h2>

Step-by-step explanation:

Using the vector formula u.v = |u||v|cos\theta

|u| = magnitude of vector u

|v| = magnitude of vector v

u.v is the dot product of vector u and v

Given |u| = 88, |v| = 99 and u.v = 77, to get \theta we will substitute the given values into the equation above;

77 = 88*99cos\theta\\cos\theta = \frac{77}{88*99} \\cos\theta = \frac{77}{8712} \\cos\theta = 0.008838\\\theta = cos^{-1} 0.008838\\\theta = 89.5^{0}

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3 years ago
Find the volume of a sphere if the surface area of the sphere is 64π cm²? Explain your
yarga [219]

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the answer is 85.33π cm

Step-by-step explanation:

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