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4 years ago

10

A long distance telephone company advertised the rates of 5 minutes for 85¢ and 10 minutes for $1.10.

1 answer:

zhuklara [117]4 years ago

8 0

Let x represent the number of minutes and y the cost. Then
y - 0.85 = (1.10 - 0.85)/(10 - 5) (x - 5)
y - 0.85 = 0.25/5 (x - 5) = 1/20 (x - 5) = 1/20 x - 1/4
y = 0.05x - 0.25 + 0.85 = 0.05x + 0.6
y = 0.05x + 0.6

The cost of 25 minutes = 0.05(25) + 0.6 = 1.25 + 0.6 = $1.85

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Answer:

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Step-by-step explanation:

Given:

60% of the students are girls

40% of the students like to dance

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Percentage of the girls in the party = 58%

To Find:

How many students now at the party like to dance=?

Solution:

Let the number of girls be g.

Let the number of total people originally be t.

We know that

$\frac{g}{t}=\frac{60}{100}$

$\frac{g}{t}=\frac{3}{5}$ ----------------------------------(1)

We also know that

$\frac{g}{t+20}=\frac{58}{100}$

$\frac{g}{t+20}=\frac{29}{50}$ -----------------------------(2)

We now have a system of equation from (1) and (2)

3t=5g

$g = \frac{3t}{5}$ ------------------------(3)

50g=29t+580------------------------(4)

Substituting 3 in 4, we get

$50(\frac{3t}{5})=29t+580$

$(\frac{150t}{5})=29t+580$

$30t =29t+580$

$30t -29t = 580$

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So originally there was 580 students

In this 580 students 40% liked to dance

Then the number of students liked to dance =

=> $40\% \text{of} 580$

=> $\frac{40}{100} \times 580$

=> $0.4 \times 580$

=> 232

We also know that with these people, 20 boys joined, all of whom like to dance.

Now the number of students like to dance = 232+20 = 252 students

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