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Elza [17]
2 years ago
14

It's the computer seice can u help me

Mathematics
2 answers:
Natasha_Volkova [10]2 years ago
7 0

Answer:

yes it can help in some ways I think

Dmitrij [34]2 years ago
5 0

Answer:

I can help you, just tell me what it is.

Step-by-step explanation:

Step 1: Tell me the problem

Step 2: Wait for a response.

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A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by V = x2h
Tanya [424]

Answer:

  192 cm^3/min

Step-by-step explanation:

Differentiating the volume expression, we get ...

  dV/dt = 2xh(dx/dt) +x^2(dh/dt)

We are given that ...

  x = 4 cm, dx/dt = 2 cm/min, h = 15 cm, dh/dt = -3 cm/min

Putting these values into the formula for volume rate of change, we get ...

  dV/dt = 2(4 cm)(15 cm)(2 cm/min) +(4 cm)^2(-3 cm/min)

  = 240 cm^3/min -48 cm^3/min

  dV/dt = 192 cm^3/min

8 0
3 years ago
What are the next 3 numbers in this sequence? 1,1,2,4,7,13,24,44
Bogdan [553]
81,149, 274.... adding three numbers from the last would help you

like if you take 7 = 4 + 2 +1

or 13 = 7 + 4 +2

similarly 44+24+13 = 81
              81+44 +24 = 149
              149 + 81 +44 = 274

hope you get it!

6 0
4 years ago
52/21 in its simplest form as a mixed number
Sliva [168]

Answer:

2\frac{10}{21}

Step-by-step explanation:

1. find out how many times 21 can go into 52 (answer- 2 times)

2. find the remainder (answer- 10)

3. put the remainder over 21 (10/21)

4. make it a mixed number (2 10/21)

7 0
4 years ago
At a car wash, customers can choose the type of wash and whether to use the interior vacuum. Customers are equally likely to cho
tensa zangetsu [6.8K]
There are 4 possible outcomes based on 2 types of wash (deluxe wash & other wash) and 2 vacuum uses (with vacuum and no vacuum). Since customers are equally likely to choose between these, we can run a uniform distribution from 1-4, where each represents one outcome. For example, 1 = deluxe+vacuum, 2=deluxe+no vacuum, 3=other wash+vacuum, 4=other wash+no vacuum. Then after running a large number of simulations (ex. 1000), count the number of the desired result (which is the number 2), and divide by the total number. This will give the probability.
4 0
3 years ago
Annie and her friends are playing a game called doubles. In the game, a player rolls two dice at the same time. The outcome of e
KatRina [158]
There are 6 possible outcomes for die A and 6 possible outcomes for die B.
Each of the 6 outcomes of die A can be combined with each of the 6 outcomes of die B. Therefore the total number of possible outcomes for each roll is given by:
6\times6=36
3 0
4 years ago
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