Answer:
6. Line graph
Step-by-step explanation:
It shows how information changes over time
The capital formation of the investment function over a given period is the
accumulated capital for the period.
- (a) The capital formation from the end of the second year to the end of the fifth year is approximately <u>298.87</u>.
- (b) The number of years before the capital stock exceeds $100,000 is approximately <u>46.15 years</u>.
Reasons:
(a) The given investment function is presented as follows;

(a) The capital formation is given as follows;

From the end of the second year to the end of the fifth year, we have;
The end of the second year can be taken as the beginning of the third year.
Therefore, for the three years; Year 3, year 4, and year 5, we have;

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87
(b) When the capital stock exceeds $100,000, we have;
![\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%20%5Cmathbf%7B%5Cleft%5B1000%20%5Ccdot%20%20e%5E%7B0.1%20%5Ccdot%20t%7D%7D%20%2B%20C%20%5Cright%5D%5Et_0%7D%20%3D%20100%2C000)
Which gives;




The number of years before the capital stock exceeds $100,000 ≈ <u>46.15 years</u>.
Learn more investment function here:
brainly.com/question/25300925
Option D:

Solution:
Given function:

To find the inverse of the function.
<u>Inverse of a function:</u>
<em>If a function f(x) is mapping x to y, then the inverse function of f(x) maps y back to x.</em>

Interchange the variables x and y.

Now, solve for y.
Multiply both sides by (y - 5).

Cancel the common factors, we get

Divide by x on both sides.

Add 5 on both sides.


To make the denominator same, multiply the 2nd term by
.



Option D is the correct answer.
Since 6x6 equals 36, then 6² would be the exponent because 6² is the same as 6x6