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3 years ago

Can anyone help me please?

Mathematics

2 answers:

NemiM [27]3 years ago

6 0

Answer: r = -6

(5,-6) (3,-2)

vovangra [49]3 years ago

4 0

Answer:

- 6

Step-by-step explanation:

The given statement implies that the slope of line formed by (5, r) is (3, -2) is -2, as they lie on the same line.

Slope(using these pts) = (y2 - y1)/(x2 - x1)

=> - 2 = (-2 - r)/(3 - 5)

=> -2 = (-2 - r)/(-2)

=> (-2)(-2) = (-2 - r)

=> 4 = -2 - r

=> r = - 2 - 4

=> r = - 6

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gtnhenbr [62]

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3 years ago

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3 years ago

In ΔJKL, the measure of ∠L=90°, JL = 24, LK = 7, and KJ = 25. What is the value of the sine of ∠K to the nearest hundredth?

podryga [215]

Given:

Given that JKL is a right triangle.

The measure of ∠L is 90°

The length of JL = 24, LK = 7, and KJ = 25.

We need to determine the value of sine of ∠K.

Value of sin ∠K:

The value of sin ∠K can be determine using the trigonometric ratio.

Thus, we have;

$sin \ \theta=\frac{opp}{hyp}$

Substituting $\theta=K$ , the side opposite to angle K is JL and the hypotenuse is JK

Thus, we have;

$sin \ K=\frac{JL}{JK}$

Substituting JL = 24 and JK = 25, we get;

$sin \ K=\frac{24}{25}$

Simplifying, we get;

$sin \ K=0.96$

$K=sin^{-1}(0.96)$

$K=73.74^{\circ}$

Thus, the measure of sine of ∠K is 73.74°

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3 years ago