Answer:
The number of mol is: 0, 042 mol in 4 grams of MgCl2
Explanation:
We calculate the weight of 1 mol of MgCl2:
Weight 1mol of MgCl2= weight Mg + (weight Cl)x 2=
24, 3 grams + 2 x 35, 5 grams = 95, 3 grams/mol MgCl2
95, 3 grams------1 mol MgCl2
4 grams -------x = (4 grams x1 mol MgCl2)/ 95, 3 grams= 0, 04197 mol MgCl2
Answer :
= -1622.8 J/K
= -94.6 J/K
= 0 J/K
Explanation : Given,
= -483.6 kJ
The given chemical reaction is:

First we have to calculate the value of
.



Entropy of system = -1622.8 J/K
As we know that:
Entropy of system = -Entropy of surrounding = 1622.8 J/K
and,
Entropy of universe = Entropy of system + Entropy of surrounding
Entropy of universe = -1622.8 J/K + (1622.8 J/K)
Entropy of universe = 0
You would have to run 100 kilometers across it once. Then you will have to run 10 meters across it because a football field is 110 meters according to the NFL’s website
The answer is 3.25 x 10 -3 kg is not equal to 325 cg