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Sliva [168]
3 years ago
8

In a first-order decomposition reaction, 50.0% of a compound decomposes in 10.5 min.

Chemistry
1 answer:
mihalych1998 [28]3 years ago
8 0

In this reaction 50% of the compound decompose in 10.5 min thus, it is half life of the reaction and denoted by symbol t_{1/2}.

(a) For first order reaction, rate constant and half life time are related to each other as follows:

k=\frac{0.6932}{t_{1/2}}=\frac{0.6932}{10.5 min}=0.066 min^{-1}

Thus, rate constant of the reaction is 0.066 min^{-1}.

(b) Rate equation for first order reaction is as follows:

k=\frac{2.303}{t_{1/2}}log\frac{[A_{0}]}{[A_{t}]}

now, 75% of the compound is decomposed, if initial concentration [A_{0} ] is 100 then concentration at time t [A_{t} ] will be 100-75=25.

Putting the values,

0.066 min^{-1}=\frac{2.303}{t}log\frac{100}{25}=\frac{2.303}{t}(0.6020)

On rearranging,

t=\frac{2.303\times 0.6020}{0.066 min^{-1}}=21 min

Thus, time required for 75% decomposition is 21 min.

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A first-order reaction has a half-life of 20.0 minutes. Starting with 1.00 × 1020 molecules of reactant at time t = 0, how many
zalisa [80]

Half-life time of a reaction is time at which reactant concentration becomes half of its initial value.

Half-life of the first order reaction is 20 min. Rate constant can be calculated as follows:

K=\frac{0.6932}{t_{1/2}}=\frac{0.6932}{20 min}=0.03466 min^{-1}

The rate expression for first order reaction is as follows:

k=\frac{2.303}{t}log\frac{A_{0}}{A_{t}}

initial number of molecules of reactant are 10^{20}, time is 100 min thus, putting the values to calculate number of reactant at time 100 min,

0.03466 min^{-1}=\frac{2.303}{100 min}log\frac{[10^{20}]}{A_{t}}

On rearranging,

\frac{10^{20}}{A_{t}}=31.988

Or,

A_{t}=3.13\times 10^{18}

Therefore, number of molecules unreacted will be 3.13\times 10^{18}

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3 years ago
The radio station z107.7 broadcasts radio waves. What do the numbers 107.7 represent?
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6 0
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Determine the oh of a solution that is 0.220 m in hco3
ICE Princess25 [194]

Answer : The hydroxide ion concentration of a solution is, 5\times 10^{-14}

Explanation :

As we know that HCO_3^- dissociates in water to give hydrogen ion (H^+) and carbonate ion (CO_3^{2-}).

As, 1 mole of HCO_3^- dissociates to give 1 mole of hydrogen ion (H^+)

Or, 1 M of HCO_3^- dissociates to give 1 M of hydrogen ion (H^+)

So, 0.200 M of HCO_3^- dissociates to give 0.200 M of hydrogen ion (H^+)

Now we have to calculate the hydroxide ion concentration.

As we know that:

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Therefore, the hydroxide ion concentration of a solution is, 5\times 10^{-14}

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<h2>Answer:</h2>

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5 0
3 years ago
Determine if the results of the following word problem adhere to the Law of Conservation of Mass. 1. A chemist combines 4.9 g of
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Answer: The results agree with the law of conservation of mass

Explanation:

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