Question

In a population that is in Hardy-Weinberg equilibrium, 64% of the individuals express the recessive phenotype for a particular gene locus. What is the expected frequency of the recessive allele in this population?

Answer 1

Answer:

Expected frequency of the recessive allele in this population $= 80$%

Explanation:

Given -

Recessive phenotype expressed by an individuals for a particular gene locus is $64$%

Now as per Hardy-Weinberg equilibrium equation, the frequency of individual with recessive phenotype is represented by "$q^{2}$"

where "q" is the frequency for recessive allele.

Thus,

q $= \sqrt{q^2} \\= \sqrt{0.64} \\= 0.8$

Expected frequency of the recessive allele in this population $= 80$%