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2 years ago

Solve: 8x2 + 64x = 0. x = 0, x = −8 x = 0, x = 8 x = −8, x = 0, x = 8 x = 8, x = 64

Mathematics

1 answer:

blagie [28]2 years ago

4 0

$8x^2+64x=0\\
8x(x+8)=0\\
x=0 \vee x=-8$

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A quadratic function is a function of the form y=ax^2+bx+c where a, b, and c are constants. Given any 3 points in the plane, the

pochemuha

Answer:

The quadratic function whose graph contains these points is $y=-x^{2}-2x-2$

Step-by-step explanation:

We know that a quadratic function is a function of the form $y=ax^{2}+bx+c$ . The first step is use the 3 points given to write 3 equations to find the values of the constants a,b, and c.

Substitute the points (0,-2), (-5,-17), and (3,-17) into the general form of a quadratic function.

$-2=a*0^{2}+b*0+c\\c=-2$

$-17=a*-5^{2}+b*-5+c\\c=-25a+5b-17$

$-17=a*3^{2}+b*3+c\\ c=-9a-3b-17$

We can solve these system of equations by substitution

Substitute $c=-9a-3b-17$

$-9a-3b-17=25a+5b-17\\-9a-3b-17=-2$

Isolate a for the first equation

$-9a-3b-17=-25a+5b-17\\a=\frac{b}{2}$

Substitute $a=\frac{b}{2}$ into the second equation

$-9\left(-\frac{b}{2}\right)-3b-17=-2$

Find the value of b

$-9\left(-\frac{4b}{17}\right)-3b-17=-2\\ b=-2$

Find the value of a

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The solutions to the system of equations are:

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2 years ago

The perimeter of a rectangle is 16.6km, and its area is 13.42km2. Find its length and width. length : km width : km

Otrada [13]

Answer:

l=5.12 & w=2.62

Step by step explanation:

A=l×w

13.42=lw

w=13.42/l

$p = 2(l + w) \\ 16.6 = 2(l + \frac{13.42}{l} ) \\ 16.6 = 2( \frac{ {l}^{2} + 13.42}{l}) \\ 16.6 = 2(l + 13.42) \\ 16.6 = 2l + 26.84 \\ 2l = 26.84 - 16.6 \\ 2l = 10.24 \\ l = \frac{10.24}{2} \\ l = 5.12km$

Since you have found the value of the length you can find the value.of the width.

$w = \frac{13.42}{l} \\ w = \frac{13.42}{5.12} \\ w = 2.62km$

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2 years ago

What is the coefficient of n^2 in the sum of -5^4+4n^2-n+5 and 7n^4-5n^3-9n^2+3n+2

pickupchik [31]

Hello :
-5^4+4n^2-n+5 : the coefficient of n^2 is : 4
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2 years ago