Answer:
6°F
58°F
Step-by-step explanation:
From the data Given :
Temperature rise in Buffalo by noon time = 14°F
The initial temperature at Buffalo = - 8°F
Rise in temperature = 14°F
Therefore, temperature at noon = (-8 + 14)°F = 6°F
B.)
Temperature at 6am in St. Louis = 32°F
Temperature at 6am in Juneau = - 26°F
Temperature difference :
(32 - (-26))°F
32 + 26
= 58°F
Temperature in St. Louis is 58°F higher
(a) The lateral surface area of the prism is 720 sq units and the total surface area is 752 sq units.
(b) The lateral surface area of the cone is 136π sq units and the total surface area is 200π sq units.
(c) The lateral surface area of the cylinder is 242π sq units and the total surface area is 484π sq units.
<h3>
Lateral surface area of the prism</h3>
L.S.A = Ph
where;
- P is perimeter of the base
- h is height of the prism
h² = 17² - 8²
h² = 225
h = 15
L.S.A = (3 x 16) x 15 = 720 sq units
<h3>Total s
urface area of the prism</h3>
T.S.A = PH + 2B
T.S.A = 720 + 2(16) = 752 sq units
<h3>
Lateral surface area of the cone</h3>
L.S.A = πrt
where;
- t is the slant height = 17
r² = 17² - 15²
r² = 64
r = 8
L.S.A = π(8)(17) = 136π sq units
<h3>
Total surface area of the cone</h3>
T.S.A = πrt + πr²
T.S.A = 136π sq units + π(8)²
T.S.A = 200π sq units
<h3>
Lateral surface area of the cylinder</h3>
L.S.A = 2πrh
where;
- r is the radius of the cylinder = 11
- h is height of the cylinder = 11
L.S.A = 2π(11 x 11) = 242π sq units
<h3>Total
surface area of the cylinder</h3>
T.S.A = 2πrh + 2πr² = 2πr(r + h)
T.S.A = 2π(11)(11 + 11)
T.S.A = 484π sq units.
Thus, the lateral surface area of the prism is 720 sq units and the total surface area is 752 sq units.
- the lateral surface area of the cone is 136π sq units and the total surface area is 200π sq units.
- the lateral surface area of the cylinder is 242π sq units and the total surface area is 484π sq units.
Learn more about surface area here: brainly.com/question/76387
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