Y= -6 --> plug this -6 into the y of the 2nd equation
y= 4x+12 --> -6 = 4x+12 --> 4x = -18
x = -18/4 = -9/2 --> now this is the x solution coordinate, and we know that y must equal -6 from the 1st equation, so our solution point is:
(-9/2, -6)
Hope that helped!
A right triangle's longest side is the hypotenuse
let x=longest, y=middle, and z=shortest
x=y+2
y=2z-1
therefore x=(2z-1)+2=2z+1
find z
z^2+y^2=x^2 by Pythagorean theorem
plug in x and y in terms of z
z^2+(2z-1)^2=(2z+1)^2
z^2+4z^2-4z+1=4z^2+4z+1
subtract the right-hand side's value from the left-hand side's
z^2-8z=0
z(z-8)=0
z=0, 8
z cannot be zero as the sides must have some value to it.
Therefore the shortest side is equal to 8







The absolute value of a real number a is a when a≥0, or -a when a<0. The absolute value of -6 is 6. The absolute value of 4 is 4.
#IfWrongPleaseReport
#StudyTogetherWithMe
#ILoveMath
Mallory purchased 8 oranges.
6*0,75+n*1,25=14,50
Answer:
I think its c but I'm not sure. You need to ask a professional.
Step-by-step explanation: