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mixer [17]
3 years ago
7

Một xạ thủ bắn 10 viên đạn vào một mục tiêu, với xác suất bắn trúng mục tiêu ở mỗi lần bắn là p=0,8. Biết rằng, nếu cả 10 viên đ

ạn trúng mục tiêu thì mục tiêu chắc chắn bị phá hủy. Nếu có từ 2-9 viên đạn trúng mục tiêu, thì mục tiêu bị há hủy với xác suất là 80%. Nếu chỉ có 1 viên đạn trúng mục tiêu | thì mục tiêu bị phá hủy với xác suất là 20%. Tính xác suất để mục tiêu bị phá hủy?
Mathematics
1 answer:
strojnjashka [21]3 years ago
8 0

Answer:

Step-by-step explanation:

A gunner fires 10 bullets at a target, with the probability of hitting the target at each shot is p = 0.8. Know that, if all 10 bullets hit the target, the target is definitely destroyed. If 2-9 bullets hit the target, the target is destroyed with a probability of 80%. If only 1 bullet hits the target | then the target is destroyed with a probability of 20%. What is the probability that the target is destroyed?

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When rolling two six-sided number cubes, what is the probability of getting a sum of at least 5? 5/18 1/3 13/18 5/6
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The sample space for two six sided cubes =

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)


Now the favourable events are those where the sum is greater than or equal to 5.

It means

(1,4) (1,5) (1,6)

(2,3) (2,4) (2,5) (2,6)

(3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)


It means

favourable events = 30

and total possible events = 36


So probability = 30/36   = 5/6

Hence 4th option is the correct one.

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Step-by-step explanation:

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