Question

Find the volume of a right circular cone that has a height of 3.9 ft and a base with a radius of 14.7 ft. Round your answer to the nearest tenth of a cubic foot.

Answer 1

Answer:

Volume of the cone = $882.08feet^2$

Step-by-step explanation:

Volume of a right circular cone:

                $=\pi *r^2*\frac{h}{3}$

For,  h=3.9 feet

        r= 14.7 feet

As, $\pi =\frac{22}{7}=3.14$

 Volume :

                  $=3.14*(14.7*14.7)*\frac{3.9}{3} \\\\=3.14*216.09*1.3\\\\=3.14*280.92\\\\=882.08feet^2$

Volume of the cone is $882.08feet^2$