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3 years ago

Can someone help me

Mathematics

2 answers:

Vladimir79 [104]3 years ago

7 0

Answer:

sure, but what is there to help with?

Step-by-step explanation:

Hoochie [10]3 years ago

3 0

Same dudeeeee ahahhahah

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The length of a rectangle is 2 times the width of the rectangle. Let x represent the width of the rectangle.

nikitadnepr [17]

Answer:

ok ASAP done ..... for it

4 0

3 years ago

Given that the average rate of change for y = f(x) over the interval [0,3] is −1, the average rate of change over the interval [

Svet_ta [14]

Answer:

Answer is 2

Step-by-step explanation:

We know that average rate of change of a function f(x) in the interval (a,b) is

$\frac{1}{b-a} \int\limits^a_b {f(x)} \, dx$

Using this we can say that

$\int\limits^0_3 {f(x)} \, dx =-1(3)=-3\\\int\limits^2_3 {f(x)} \, dx =5(1)=5\\\\\int\limits^2_6 {f(x)} \, dx =4(5)=20\\$

Using properties of integration we have

3 to 6 integral = 20-5 =15

0 to2 integral = -3=5 =-8

Thus integral form 0 to 6 would be = -8+15+5 = 12

Average rate of change form 0 to 6 = $\frac{12}{6} =2$

Answer is 2

7 0

3 years ago

Why is 21/100 greater than 1/5

storchak [24]

Because 21 is more than 1

8 0

3 years ago

Read 2 more answers

How to solve these two problems ？

puteri [66]

8) $\theta$ is -0.896 radians

9) length of arc is 41.91 cm

Solution:

Given that,

$tan\ \theta = \frac{-5}{4}$

$\theta$ is in quadrant 4

To find: $\theta$

From given,

$tan\ \theta = \frac{-5}{4}\\\\\theta = tan^{-1} \frac{-5}{4}\\\\\theta = tan^{-1} (-1.25)\\\\\theta = -51.34$

Thus value of $\theta$ is -51.34 degrees

Convert degrees to radians

$-51.34\ degree = -51.34 \times \frac{ \pi }{180}\ radian\\\\-51.34\ degree = -0.896\ radian$

Thus $\theta$ is -0.896 radians

From given,

radius = 15.4 cm

$\theta = \frac{13 \pi }{15}$

<em><u>The length of arc when angle in radians is:</u></em>

$arc\ length = r \times \theta\\\\arc\ length = 15.4 \times \frac{ 13 \pi }{15}\\\\arc\ length = 15.4 \times 2.721\\\\arc\ length = 41.91$

Thus length of arc is 41.91 cm

4 0

3 years ago

Is X-1 a factor of x^5-1?

Musya8 [376]

Answer: No

Explanation:

According to factor theorem, if f(x)=0 then x is a factor of the given function or equation.

As x-1 is a factor

We equate x-1=0

x=1

Substituting in x^5-1, we have 1^5-1 =1-1=0.

Hence, it's a factor.

When coming to x^5+1, it would become 1^5+1=1+1=2

So x-1 isn't a factor of x^5+1.

4 0

2 years ago

Can someone help me​

Can someone help me