ANSWER:
In triangles BEC and AED
1)BC=AD(given)
2)Angle BCD= Angle ADC(given)
Then,Angles BCE=Angle ADE
3)Angle BEC=Angle AED(vertically opposite angles)
Thus,triangleBEC=~triangle AED( by AAS rule)
Thus,DE=CE (By CPCTC)
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2x77}{x} theis way is the best answee
Answer:
C.
Step-by-step explanation:
Answer:
-13
Step-by-step explanation:
2.5 * 2 = 5.
3.6 * 5 = 18.
5 - 18 = -13
X - the mass of the first alloy (15%)
y - the mass of the second alloy (75%)
x kg of the first alloy contains 15%x=0.15x=(15/100)x=(3/20)x kg of copper
y kg of the second alloy contains 75%y=0.75y=(75/100)y=(3/4)y kg of copper
90 kg of a 51% copper alloy contains 51%*90=0.51*90=45.9 kg of copper

The metal worker should combine 36 kg of the 15% copper alloy and 54 kg of the 75% copper alloy to create 90 kilograms of a 51% copper alloy.