Answer:
32
Step-by-step explanation:
We let the length of the square be l, the diagonal be z and the area be A.
Then by Pythagoras theorem;

The are of a square of length l is given as;

Combining these two equations yields;


Next, we have been given;

We are required to find;
when z = 4
By chain rule;

Differentiating
with respect to z yields;

Therefore,
= 8z
When z is 4m the area of the square will be increasing at a rate of;
8m/min * 4m = 32
Answer =
1. SAS
2. SSS
3. ASA
4. SSS
5. SAS
6. AAS
Answer =yes, the residuals would tend to be one sided
The answer to the question

When
![t=\cos A+\sin A\in[-\sqrt{2};\sqrt{2}]\approx[-1.4142;1.4142]](https://tex.z-dn.net/?f=%20t%3D%5Ccos%20A%2B%5Csin%20A%5Cin%5B-%5Csqrt%7B2%7D%3B%5Csqrt%7B2%7D%5D%5Capprox%5B-1.4142%3B1.4142%5D%20)
and there is only one answer t = 1.
For
both values are correct.