You find the square root of 576. The answer is 24
Answer:
Dh/dt = 0.082 ft/min
Step-by-step explanation:
As a perpendicular cross section of the trough is in the shape of an isosceles triangle the trough has a circular cone shape wit base of 1 feet and height h = 2 feet.
The volume of a circular cone is:
V(c) = 1/3 * π*r²*h
Then differentiating on both sides of the equation we get:
DV(c)/dt = 1/3* π*r² * Dh/dt (1)
We know that DV(c) / dt is 1 ft³ / 5 min or 1/5 ft³/min
and we are were asked how fast is the water rising when the water is 1/2 foot deep. We need to know what is the value of r at that moment
By proportion we know
r/h ( at the top of the cone 0,5/ 2) is equal to r/0.5 when water is 1/2 foot deep
Then r/h = 0,5/2 = r/0.5
r = (0,5)*( 0.5) / 2 ⇒ r = 0,125 ft
Then in equation (1) we got
(1/5) / 1/3* π*r² = Dh/dt
Dh/dt = 1/ 5*0.01635
Dh/dt = 0.082 ft/min
Answer: 79%
That’s because it’s the middle probability it can’t be others because they are too high it too low
Well if you add 14 and 21 you get 35. with 35 you can have 7 groups of 5 but if they have to be equal with the number of boys and girls in each group it would still be 7. two boys in each group with three girls in each group.
8.5b.
7a= 5a +3b
-5a -5a
2a = 3b
/2
a= 1.5b
Solve by substitution and you get;
8.5b=8.5b
Because of the lack of constants in the equation there isn't a definite answer.
