Question

An isosceles triangle ABC has its vertices on a circle. If AB =13 cm BC= 13cm and AC= 10cm calculate the height BM of the triangle

Answer 1

Answer:

$BM = 12\,cm$

Step-by-step explanation:

The height BM of the triangle can be determined by using the Pythagorean theorem:

$BM = \sqrt{BC^{2}-\left(\frac{1}{2}\cdot AC \right)^{2}}$

$BM = \sqrt{(13\,cm)^{2}-(5\,cm)^{2}}$

The height of the isosceles triangle is:

$BM = 12\,cm$