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Sergio039 [100]
3 years ago
11

Rewrite sin(x)cos2(x) − sin(x) as an expression containing a single term

Mathematics
1 answer:
Veronika [31]3 years ago
8 0

Answer:   -2sin³x

Step-by-step explanation:

cos ( x + y ) = cosx*cosy - sin y*sinx         (1)

if  x = y  (1)  could be express as: cos (2x) = cosx*cosx -sinx*sinx

cos 2x = cos²x -sin²x

Then   sin(x)*cos2(x) − sin(x)      ⇒ sinx * ( cos²x - sin²x ) - sinx

multiplying  sinx*cos²x -sin³x  -sinx

sinx (commom factor  sinx (cos²x -sin²x -1)    but   1-cos²x = sin²x

or -1 +cos²x = -sin²x          ⇒sinx( -sin²x -sin²x)   ⇒sinx (-2sin²x)

-2sin³x

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prisoha [69]

Answer:

t = 5

Step-by-step explanation:

  1. 19 + 4t = 39
  2. 4t = 20 Subtract 19 from 39
  3. \frac{4t}{4} = \frac{20}{4} Divide by 4
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3 years ago
A farmer has 7 3/4 rows of radishes in one field, 4 3/4 rows of radishes in another field, and 6 1/4 rows of radishes in a third
Gala2k [10]

Answer:

  A. 18 3/4

Step-by-step explanation:

It is convenient to rearrange the sum to make it easier to compute:

  7 3/4 + 4 3/4 + 6 1/4 = (7 3/4) +(4 +6) +(3/4 +1/4)

  = 7 3/4 + 10 + 1

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The farmer has 18 3/4 rows of radishes altogether.

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3 years ago
Please help. right answer will be brainliest.
jek_recluse [69]

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24 square units

Step-by-step explanation:

6×4=24

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KatRina [158]

Answer:

Vel_jet_r =  (464.645 mph)  North + (35.35 mph) East

||Vel_jet_r|| =  465.993 mph

Step-by-step explanation:

We need to decompose the velocity of the wind into a component that can be added  (or subtracted from the velocity of the jet)

The velocity of the jet

500 mph North

Velocity of the wind

50 mph SouthEast = 50 cos(45) East + 50 sin (45) South

South = - North

Vel_ wind = 50 cos(45) mph  East  -  50 sin (45) mph North

Vel _wind =  35.35 mph  East  -  35.35 mph North

This means that the resulting  velocity of the jet is equal to

Vel_jet_r =  (500 mph - 35.35 mph) North + 35.35 mph East

Vel_jet_r =  (464.645 mph)  North + (35.35 mph) East

An the jet has a magnitude velocity of

||Vel_jet_r|| =  sqrt ((464.645 mph)^2 + (35.35 mph)^2)

||Vel_jet_r|| =  465.993 mph

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