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maxonik [38]
3 years ago
12

if p(x) = x+ 7/ x-1 and q (x) = x^2 + x - 2, what is the product of p(3) and q(2)? a. 50 b. 45 c. 40 d. 20 e. 6

Mathematics
1 answer:
Amanda [17]3 years ago
6 0

Answer:

d. 20

Step-by-step explanation:

To answer the question given, we will follow the steps below:

we need to first find p(3)

p(x) = x+ 7/ x-1

we will replace all x by 3 in the equation above

p(3) = 3+7 / 3-1

p(3) = 10/2

p(3) = 5

Similarly to find q(2)

q (x) = x^2 + x - 2,

we will replace x by 2 in the equation above

q (2) = 2^2 + 2 - 2

q (2) = 4 + 0

q (2) = 4

The product of p(3) and q(2)   =   5 × 4   = 20

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If 541 people use the swimming pool and children pay 1.75 dollars and adults pay 2.25 and in total earned was 1041.25 how many c
Zina [86]

Answer:

352 children

Step-by-step explanation:

Solve algebraically using a system of equations

Assign variables

let "a" be the number of adults

let "c" be the number of children    <-- We want to find this

a + c = 541             Equation for number of people

2.25a + 1.75c = 1041.25           Equation for money

<u>Rearrange the equation for people</u>. Isolate the variable you don't want to find.

a = 541 - c

<u>Substitute</u> "541 - c", replacing "a", in the equation for money

2.25a + 1.75c = 1041.25              

2.25(541 - c) + 1.75c = 1041.25               Distribute over brackets

1217.25 - 2.25c + 1.75c = 1041.25               Collect like terms

1217.25 - 0.5c = 1041.25                   Simplified equation

<u>Start isolating "c".</u> Move anything that's not "c" to the right side. Move numbers in reverse BEDMAS order. That means we will add/subtract before dividng/multiplying. When moving a number, do its reverse operation to the entire equation.

1217.25 - 0.5c = 1041.25      Do the reverse of positive 1217.25

1217.25 - 1217.25 - 0.5c = 1041.25 - 1217.25    Subtract 1217.25 on both sides  

-0.5c = -176               Do the reverse of multiplying by -0.5

-0.5c/-0.5 = -176/-0.5               Divide both sides by -0.5

c = 352                Number of children

Therefore, there were 352 children in the pool.

5 0
3 years ago
A photocopier increased the sides of a square in the ratio 4:5.
Svetach [21]

Answer:

The sides are increased by a percentage of 25%

Step-by-step explanation:

Let

x -----> the length side of the original square

y ----> the length side of the increased square

we have

\frac{x}{y} =\frac{4}{5}

y=\frac{5}{4}x

y=1.25x

the increase is calculated by subtracting x from y

so

y-x=1.25x-x=0.25x

Remember that

0.25=\frac{25}{100}=25\%

therefore

The sides are increased by a percentage of 25%

4 0
3 years ago
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