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2 years ago

Someone help me pls

Mathematics

1 answer:

koban [17]2 years ago

6 0

Answer:

ydyysyescdcvd dvvshdhdhxxbxbxhxhbxhhxxbhxhxbxbgbcbcbbchchchchchchchchhchchcbcbcbcbchcjcj

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Why does the shape of the moon appear to change over the course of about a month? (2 points)

kirill [66]

B. The sun is lighting up different amounts of the moon

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2 years ago

Mrs. Gainey planned a dinner for 15 people this Thanksgiving. She bought 22.5 lbs of turkey, plus potatoes, cranberry salad, rol

likoan [24]

Each person was to have 1.5 pounds of turkey, but, with the extra people she would have to buy an additional 4.5 pounds of turkey. If she didn’t buy anymore turkey then everyone would get 1.25 pounds of turkey, which is about 1/6 less of what they would have originally gotten. 1/6 is equal to 16.7% or 0.167.

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3 years ago

What is the range of the data set below?<br><br> 56, 42, 48, 32, 17, 26, 92

Digiron [165]

Answer:

edit: 92-17=75

Step-by-step explanation:

when using range you subtract the highest number with the lowest

3 0

3 years ago

Can someone help pls omg

hodyreva [135]

Answer:

see explanation

Step-by-step explanation:

Sum the sides of both polygons and equate.

(20)

x + 4 + x + 2 + x + 5 = 2(x + 1) + 2(x + 3) ← distribute parenthesis

3x + 11 = 2x + 2 + 2x + 6

3x + 11 = 4x + 8 ( subtract 3x from both sides )

11 = x + 8 ( subtract 8 from both sides )

3 = x

(21)

5(12x) = x + 7 + 6x + 9 + x + 10

60x = 8x + 26 ( subtract 8x from both sides )

52x = 26 ( divide both sides by 52 )

x = $\frac{26}{52}$ = $\frac{1}{2}$

4 0

2 years ago

Does anyone know the answer to this one?

polet [3.4K]

Answer:

$\large\boxed{a(x+4)(x-5)=0,\ a\in\mathbb{R}-\{0\}}\\\\\text{for}\ a=1\to\boxed{x^2-x-20=0}$

Step-by-step explanation:

$\text{If}\ x_1\ \text{and}\ x_2\ \text{are the roots of the quadratic equation}\ ax^2+bx+c=0,\\\text{then}\ ax^2+bx+c=a(x-x_1)(x-x_2).\\\\\text{If}\ x_1\ \text{and}\ x_2\ \text{, then they are the roots of the quadratic equation.}\\\\\text{We have}\ x_1=-4\ \text{and}\ x_2=5.\ \text{Therefore we have the equation:}\\\\a(x-(-4))(x-5)=0\\\\a(x+4)(x-5)=0\qquad\text{for any value of}\ a\ \text{except 0}.$

7 0

3 years ago