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vova2212 [387]
2 years ago
9

Someone help me pls

Mathematics
1 answer:
koban [17]2 years ago
6 0

Answer:

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Which choice is NOT a way to find 9 ÷ 4?
olga_2 [115]
My bet is on D - 1/9 of 4 :)
8 0
3 years ago
Segment bd is perpendicular bisector of segment ac AB=9x and cb= 5x+16 what's the length of CB?
bazaltina [42]
I hope this helps you

3 0
3 years ago
What is the surface area of the cube below?
makvit [3.9K]

Answer:384

Step-by-step explanation:

5 0
3 years ago
A hotel manager believes that 27% of the hotel rooms are booked. If the manager is correct, what is the probability that the pro
AlladinOne [14]

Answer:

The probability that the proportion of rooms booked in a sample of 423 rooms would differ from the population proportion by less than 6% is 0.9946.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

 \sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}

The information provided here is:

<em>p</em> = 0.27

<em>n</em> = 423

As <em>n </em>= 423 > 30, the sampling distribution of sample proportion can be approximated by the Normal distribution.

The mean and standard deviation of the sampling distribution of sample proportion are:

\mu_{\hat p}=p=0.27\\\\\sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.27\times(1-0.27)}{423}}=0.0216

Compute the probability that the proportion of rooms booked in a sample of 423 rooms would differ from the population proportion by less than 6% as follows:

P(|\hat p-p|

                           =P(0.27-0.06

*Use a <em>z</em>-table.

Thus, the probability that the proportion of rooms booked in a sample of 423 rooms would differ from the population proportion by less than 6% is 0.9946.

6 0
3 years ago
Hellen has 10 sweets,shelly has 30 sweets.Faith has 4 fewer sweets than the average number of sweets that hellen,shelly and fait
allsm [11]

Answer:

The sum of all the sweets is 54 sweets

Step-by-step explanation:

Here, we want to calculate the number of sweets the three have altogether.

Let the number of sweet Faith has be x

Mathematically;

Faith has 4 sweets fewer than the average number of sweets

The average is the sum of all the sweets divided by 3

The average will be (10 + 30 + x)/3

Thus;

(10 + 30 + x)/3 - 4 = x

(40 + x)/3 = x + 4

40 + x = 3(x + 4)

40 + x = 3x + 12

40-12 = 3x -x

28 = 2x

x = 28/2

x = 14 sweets

So the sum of all the sweets would be 10 + 30 + 14 = 54 sweets

7 0
3 years ago
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