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cupoosta [38]
3 years ago
15

Write an equation where the left side is your power of 10 times n and the right side is the result of multiplying 0.1515... by t

hat power.
Mathematics
1 answer:
Neko [114]3 years ago
5 0

Answer:

n10^x = 0.1515x

Step-by-step explanation:

Required

Translate the statements to algebraic expression

Represent the power with x;

So, the left hand side is

<em>Power of 10: </em>10^x<em />

<em>Times n: </em>10^x * n<em />

<em />

The right hand side is:

<em>0.1515 * power of 10: </em>0.1515 * x<em />

Equate the right hand side to the left:

10^x * n = 0.1515 * x

n10^x = 0.1515x

Hence;

<em>The required expression is </em>n10^x = 0.1515x<em />

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PLEASE HELP I need the answer for this ASAP pleaseeeee
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Answer:

13

Step-by-step explanation:

f(x) = 5 \sqrt{x}  + 8 \\ f(1) = 5 \sqrt{1}  + 8 \\13

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3 0
3 years ago
And a wildlife preserve 46 ducks are captured tagged and then released. Later to her ducks are examined in four of the 200 ducks
docker41 [41]

Answer:

2300

Step-by-step explanation:

We are given that

Out of 200 , four ducks are tagged.

We have to find the number of ducks in the preserve if 46 ducks are tagged.

Let x be the number of ducks in the preserve.

If number of tagged ducks increases then number of preserved ducks also increases.It is in direct proportion.

According to question

\frac{x}{46}=\frac{200}{4}

x=\frac{200\times 46}{4}

x=50\times 46

x=2300

4 0
3 years ago
Can someone pls help??
Vlad1618 [11]

Answer:

a. The y coordinates for A are either 10 or -14

b.  The y coordinates for A are either -11 or 7

Step-by-step explanation:

distance = sqrt ((x2-x1)^2+(y2-y1)^2)

We know Point B and the x coordinate of point A as well as the distance

15 = sqrt ((-4-5)^2+(-2-y1)^2)

15 = sqrt ((-9)^2+(-2-y1)^2)

15 = sqrt (81+(-2-y1)^2)

Square each side

15^2 =sqrt (81+(-2-y1)^2)^2

225 =  81+(-2-y1)^2

Subtract 81 from each side

225-81 = 81-81 +(-2-y1)^2

144 = (-2-y1)^2

Take the square root of each side

±sqrt 144 = sqrt(-2-y1)^2

±12 = (-2-y1)

Add 2 to each side

2±12 = 2-2-y1

2±12 = -y1

14 = -y1  or -10 = -y1

Multiply by -1

-14 = y1  or 10 = y1

The y coordinates for A are either 10 or -14

Now move B to -7,-2

15 = sqrt ((-7-5)^2+(-2-y1)^2)

15 = sqrt ((-12)^2+(-2-y1)^2)

15 = sqrt (144+(-2-y1)^2)

Square each side

15^2 =sqrt (144+(-2-y1)^2)^2

225 =  144+(-2-y1)^2

Subtract 144 from each side

225-144 = 144-144 +(-2-y1)^2

81 = (-2-y1)^2

Take the square root of each side

±sqrt 81 = sqrt(-2-y1)^2

±9 = (-2-y1)

Add 2 to each side

2±9 = 2-2-y1

2±9 = -y1

11 = -y1  or -7 = -y1

Multiply by -1

-11 = y1  or 7 = y1

The y coordinates for A are either -11 or 7

3 0
3 years ago
Pleasee pleaseee help me so I can not get in trouble because my grades
liraira [26]

Answer:

she has 40 times as many

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Solve the equation 2y+4=3(2x-6) for y. Show and justify your steps.
ElenaW [278]
Hello : 
<span>2y+4=3(2x-6)
2y+4 -4 =3(2x-6)-4
2y = 6x-18-4
2y =6x-22
y =(6x-22)/2
y= 3x-11</span>
8 0
3 years ago
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