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2 years ago

Write the slope of DB

Mathematics

2 answers:

jarptica [38.1K]2 years ago

7 0

Answer: $\frac{c - 0}{b-a}$

elena-s [515]2 years ago

4 0

The slope is c/b-a i’m pretty sure

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Oliga [24]

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Step-by-step explanation:

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2 years ago

adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the

Zigmanuir [339]

Answer:

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$ and $\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

Step-by-step explanation:

The equation of the isotope decay is:

$\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }$

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

$\tau = \frac{5568\,years}{\ln 2}$

$\tau \approx 8032.926\,years$

The decay time is:

$t = 1315\,years + 2007\,years \pm 13\,years$ (There is no a year 0 in chronology).

$t = 3335 \pm 13\,years$

Lastly, the relative amount is estimated by direct substitution:

$\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659$

$\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }$

$\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661$

4 0

2 years ago

30.00

GalinKa [24]

Answer:

(13,-23)

Step-by-step explanation:

Comparing the image coordinates to the transformation rule, you see that ...

(x -4, y +15) = (9, -8)

Adding (4, -15) to these coordinates, we get ...

(x -4, y +15) +(4, -15) = (9, -8) +(4, -15)

(x-4+4, y+15-15) = (9+4, -8-15)

(x, y) = (13, -23) . . . . coordinates of D

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2 years ago

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Setler79 [48]

Answer:

1. D. is Brand B

2. 60 mikes per hour

3. is 40 mins

4. is A. 3/20 u are multiplying

Step-by-step explanation:

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2 years ago

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