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Mrrafil [7]
3 years ago
8

3f+3<6 or 7f-20 >50 I don't understand this

Mathematics
1 answer:
OLga [1]3 years ago
7 0
The answers to the questions

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What is the answer I really need help
attashe74 [19]

Answer: 27

Step-by-step explanation:

The perimeter is the lengths of all sides of the figure added together. Since all  sides are equal in this triangle, we know all sides have a length of 9. We know this because all sides have 2 little lines on them, symbolizing that they are equal.

P=9+9+9=27

5 0
3 years ago
I like risking my points for hard homework
ELEN [110]

Answer:

The triangle and the square have the same area because they both have four squares

Step-by-step explanation:

The square has four that are easily shown but the triangle has one full one but when two are split together like some of them when you put the two together they equal one whole.

Have a wonderful day/night/afternoon

7 0
2 years ago
Read 2 more answers
(-6/7) (-9/5) type as a simplified fraction ??? HELP
Llana [10]

-3/4  -3/5

i think  hopefully it is


6 0
3 years ago
Read 2 more answers
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
The product of 5 and g
stich3 [128]

Answer:

5g

Step-by-step explanation:

6 0
3 years ago
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