Answer:

Step-by-step explanation:
To find x, the following equation is generated given the available information:



Cross multiply


Collect like terms



Answer:
Step-by-step explanation:
c
Answer:
b=(2a-1)/(3a-1)
Step-by-step explanation:
a=(b-1)/(3b-2)
3ab-2a=b-1
3ab-b=2a-1
b(3a-1)=2a-1
b=(2a-1)/(3a-1)
negative multiplied by positives = negative numbers
3 x 5 = -15
negative multiplied by a negative = a positive number
-3 x -2y = +6y
so combine both gets -15 +6y
or a better way to write it is 6y-15
Answer:
Third answer (she is incorrect because she should have squared each leg length and then found the sum.)
Step-by-step explanation:
The pythagorean theorem states that a²+b²=c². This is not equivalent to (a+b)²=c² (due to FOIL expansion, this expands to a²+2ab+b²=c²).
This matches with the third answer, as she has to do a² and b≥ separately.
**This question involves expanding perfect squares, which you may wish to revise. I'm always happy to help!