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Fittoniya [83]
3 years ago
7

1. Write your answer using only positive exponents. (3ab^3c^-1)^3

Mathematics
2 answers:
pishuonlain [190]3 years ago
7 0
Maybe it is 27b^9a^3 over c^3
marishachu [46]3 years ago
6 0

Answer:

(\frac{{3ab^{3}}}{c^{1}} )^{3}

Step-by-step explanation:

(3ab^{3} c^{-1} )^{3} =(\frac{{3ab^{3}}}{c^{1}} )^{3}

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7. Solve the formula M=2P+3Q for the variable Q.
vichka [17]
The answer is <span>Q=(M−2P)/3
</span>
<span>M = 2P + 3Q

Subtract 2P from both sides:
M - 2P = 2P + 3Q - 2P
M - 2P = 3Q

Divide both sides by 3:
(M - 2P)/3 = 3Q/3
(M - 2P)/3 = Q</span>
7 0
3 years ago
207,567 to the nearest hundred thousand
Nezavi [6.7K]
The hundred thousands place is the 2. Since the place below that is 0, it rounds down.
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Read 2 more answers
Consider the following vectors in component form.
Mrac [35]

Answer:

Cartesian Coordinate System

• Also called

rectangular coordinate

system

• x- and y- axes intersect

at the origin

• Points are labeled (x,y)

Polar Coordinate System

– Origin and reference

line are noted

– Point is distance r from

the origin in the

direction of angle θ,

ccw from reference

line

– Points are labeled (r,θ)

Cartesian to Polar Coordinates

• r is the hypotenuse and θ

an angle

θ must be ccw from

positive x axis for these

equations to be vali

Step-by-step explanation:

7 0
2 years ago
What is yhe area of thr hexagon? 5cm, 8cm and 9.28 cm
xeze [42]

Answer:

2 meters

long long long long

8 0
3 years ago
Last question please
MatroZZZ [7]

Let's try an make a formula to make things easy.

_________________________________________________

Look at Andrew's pattern, it goes up 6 every time. Lets look at the 6 times table

6 times table:           6, 12, 18, 24, ...

____________________________________

First think, how would you work out the <u>7</u>th term in the <u>6</u>th times table?

You would do <u>6</u> times <u>7</u>.

So the formula for the 6th times table is:

6n     (where n is the term you want to find out)

_______________________________________

So to get the 9th term in the 6 times table, you would replace the n with 9, like so:

9th term in 6 times table = 6 x 9 = 54

______________________________________

Now lets compare the 6 times table to Andrew's pattern:

6 times table:           6, 12, 18, 24,

Andrew's pattern:     3, 9, 15, 21,

_____________________________________

If you look, you can see that Andrew's pattern is the 6 times table minus 3!

So what would be the formula for Andrew pattern?

---> it would be:  6n - 3   (since it's the 6 times table but minus 3)

_____________________________________

We can use this formula to easily work out the 20th term in Andrew's pattern!:

20th term = 6 x 20 - 3 = 120 - 3 = <u>117</u>    (remember, replace the n with 20)

______________________________________

Now let's make a formula for Ben's pattern!

Ben's pattern goes up in 5s, so lets compare it to the 5 times table:

5 times table:       5, 10, 15, 20

Ben's pattern:       3, 8, 13, 18,

The formula for the 5 times table is 5n, and Ben's pattern is the 5 times table but minus 2.

So the formula for Ben's pattern is: 5n - 2

__________________________________

<u>Now swap out the n for 20</u>  (to get the 20th term):

20th term = 5 x 20 - 2 = 100 - 2 = <u>98</u>

_________________________________________

So Andrew's 20th term is <u>117</u>, and Ben's 20th term is <u>98</u>.

All we do now is subtract them to find the difference:

117 - 98 = <u>19</u>

- - - - - - - - - - - - - - - - - - - - - - - - -

Answer:

Ben's 20th term is smaller by 19!

- - - - - - - - - - - - - - - - - - - - - - - - - -

5 0
3 years ago
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