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OlgaM077 [116]
3 years ago
7

A moving company charges a flat rate of $75 plus and additional $0.19 per mile driven. Which inequality correctly represents how

far the company must drive to earn at least $100? Round to the nearest mile.
Mathematics
2 answers:
Eduardwww [97]3 years ago
8 0
X = number of miles driven
Since <span>$0.19 per mile driven is added, that's + 0.19x
Flat rate of $75 initially, 75 + 0.19x

The inequality is at least $100 which means $100 or more.
</span><span>75 + 0.19x < 100
</span>0.19x < 25
x < 131.58
x < 132

The driver needs to drive 132 miles to earn at least $100
uranmaximum [27]3 years ago
6 0

For this case, the first thing we must do is define a variable.

We have then:

x: number of miles.

By the time the company earns at least $ 100 we have the following inequality:

0.19x + 75 \geq100

From here, we clear the value of x.

We have then:

0.19x\geq 100 - 75

0.19x\geq25

x\geq \frac{25}{0.19}

x\geq 132

Answer:

the company must drive to earn at least $ 100 more than or equal to 132 miles

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ElenaW [278]

Answer:

Part 1) a=-\frac{1}{4c^6}

Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}

therefore

a=-\frac{1}{4c^6}

Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})

simplify

a=-\frac{c^{6}}{4}

therefore

a=-\frac{1}{4c^{-6}}

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inessss [21]
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I hope this hepls you


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ruslelena [56]
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