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3 years ago

Does the point (6,3) satisfy the equation y = 4(x – 5)?

Mathematics

1 answer:

Darina [25.2K]3 years ago

5 0

Answer:

Step-by-step explanation:

plug (6,3) into the given equation to find out

3 = 4(6-5)

3 = 4(1)

3 = 4

since 3 does not equal 4, the point (6,3) does not satisfy the equation y=4(x-5)

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3 years ago

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Answer:

Required equation of tangent plane is $z=\frac{6}{5}(x-5y-11)$ .

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Given surface function is,

$f(x,y)=6-\frac{6}{5}(x-y)$

To find tangent plane at the point (5,-1,1).

We know equation of tangent plane at the point $(x_0,y_0,z_0)[/tex] is,

$z=f(x_0,y_0)+f_x(x_0,y_0)(x-x_0)+f_y(x_0,y_0)(y-y_0)\hfill (1)$

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