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lions [1.4K]
4 years ago
12

Kendra found two worms in the yard and measured them with a ruler. One worm was 7 2/3 inches long. The other worm was 2 1/6 inch

es long. How much longer was the longer worm?
Write your answer as a fraction or as a whole or mixed number.
Mathematics
1 answer:
Black_prince [1.1K]4 years ago
3 0

Answer:

5½ inches

Step-by-step explanation:

7⅔ - 2 1/6 = 7 4/6 - 2 1/6 = 5 3/6 = 5½

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Center City East Parking Garage has a capacity of 257 cars more than Center City West Parking Garage. If the combined capacity f
amid [387]
<span>Center City West = x
</span><span>Center City East = (x + 257)

Solve for x to find the capacity for Center City West and then we can find the capacity for Center City East.

(x + 257) + x = 1221
x + x + 257 = 1221
2x  + 257 - 257 = 1221 - 257
2x = 964
2x / 2 = 964 / 2
x = 482
</span><span>Center City West capacity = 482
</span>
Now to find Center City East capacity we substitute 482 for x in (x + 257) 

(x + 257) 
(482 + 257)
482 + 257 = 739

Center City East capacity  = 739
Center City West capacity = 482
5 0
3 years ago
Kinda ez please help aced+
torisob [31]

Answer:

Step-by-step explanation:

really need these points im sorry good luck tho

5 0
3 years ago
15n^2-27n-6 Factoring trinomials​
Leokris [45]
Ok first take out the GCF which is 3 in this case.
7 0
3 years ago
Farmers know that driving heavy equipment on wet soil compresses the soil and injures future crops. Here are data on the "penetr
Greeley [361]

Answer:

Step-by-step explanation:

Hello!

To see if driving heavy equipment on wet soil compresses it causing harm to future crops, the penetrability of two types of soil were measured:

Sample 1: Compressed soil

X₁: penetrability of a plot with compressed soil.

n₁= 20 plots

X[bar]₁= 2.90

S₁= 0.14

Sample 2: Intermediate soil

X₂: penetrability of a plot with intermediate soil.

n₂= 20 (with outlier) n₂= 19 plots (without outlier)

X[bar]₂= 3.34 (with outlier) X[bar]₂= 2.29 (without outlier)

S₂= 0.32 (with outlier) S₂= 0.24 (without outlier)

Outlier: 4.26

Assuming all conditions are met and ignoring the outlier in the second sample, you have to construct a 99% CI for the difference between the average penetration in the compressed soil and the intermediate soil. To do so, you have to use a t-statistic for two independent samples:

Parámeter of interest: μ₁-μ₂

Interval:

[(X[bar]₁-X[bar]₂)±t_{n_1+n_2-2;1-\alpha/2}*Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }]

t_{n_1+n_2-2;1-\alpha/2}= t_{20+19-2;1-(0.01/2)}= t_{37; 0.995}= 2.715

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{19*0.0196+18*0.0576}{20+19-2} }= 0.195= 0.20

[(2.90-2.29)±2.715*0.20\sqrt{\frac{1}{20} +\frac{1}{19} }]

[0.436; 0.784]

I hope this helps!

5 0
3 years ago
Pls answer as soon as possible<br> 1st person will be marked brainliest
OlgaM077 [116]

Answer:

Two half gallon containers can hold 1 gallon, whic is about 3.785 liters.

Step-by-step explanation

4 0
3 years ago
Read 2 more answers
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