The possible digits are:
5, 6, 7, 8 and
9. Let's mark the case when the locker code begins with a prime number as
A and the case when <span>the locker code is an odd number as
B. We have
5 different digits in total,
2 of which are prime (
5 and
7).
First propability:
</span>

<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with
5, 7 or
9 (three of five digits).
Second probability:
</span>
Answer:
9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9 9
Answer:
What is missing is -5x - 20
Step-by-step explanation:
To find this, simply solve for the parenthesis as if it were a variable of its own. This will allow you to see exactly what is missing.
8x - (x - 20) = 2x - (_______)
8x - x + 20 = 2x - (_______)
7x + 20 = 2x - (_______)
5x + 20 = - (_______)
-5x - 20 = (_______)
So the answer for the parenthesis is -5x - 20
Answer:
Step-by-step explanation:
2g + h = 2 --------------(I)
g - h = -5------------(II)
g = -5 + h
Plugin g = -5 + h in equation (I)
2(-5 + h) + h = 2 {Distributive property:a(b+c) = a*b +a*c}
(-5)*2 + h *2 + h= 2
-10 + 2h + h = 2
3h = 2 + 10
3h = 12
h = 12/3
h = 4
Substitute h= 6 in equation (I)
2g + 4 = 2
2g = 2 - 4
2g = -2
g = -2/2
g = -1
Can you resubmit your question so that I can give you a reasonable answer