Times by 3. Then divide the top backup by 3 to get 9/30. 9/30+9/30+9/30=27/30=9/10.
A. P(492 < x-bar < 512)
<span>z = (492-502)/100/√90 </span>
<span>z = -0.95 is 0.1711 </span>
<span>z = (512-502)/100/√90 </span>
<span>z = 0.95 is 0.8289 </span>
<span>b. P(505 < x-bar < 525) </span>
<span>z = (505-515)/100/ √90 </span>
<span>z = -0.95 </span>
<span>z = (525-515)/100/ √90 </span>
<span>z = 0.95 </span>
<span>P(-0.95< z < 0.95) = 0.6578 </span>
<span>P(-0.95< z < 0.95) = 0.6578 </span>
<span>c. P(484 < x-bar < 504) </span>
<span>z = (484-494)/100/√100 </span>
<span>z = -1 is 0.1587 </span>
<span>z = (504-494)/100/√100 </span>
<span>z = 1 is 0.8413 </span>
<span>P(-1< z <1) = 0.6826</span>
Answer:
1) Add 3n to both sides
2) Subtract 5 from both sides
3) Divide both sides by 6
n=3
Step-by-step explanation:
3n+5=23-3n
+3n +3n
6n+5=23
-5 -5
6n=18
/6 /6
n=3
Because the problem represents right angle we can use simple geometric functions to determine size of sides of triangle and its angles if needed.
Since we have angle at point that is 42 feets away from base of the building and we need lenght of side that is oposite from that angle that means that we need some trigonometric function that includes those 2 sides.
that function is tangens.
tan67 = oposite side/side next to angle
tan67 = x/42
x = 42*tan67
x = 98.94 feet
Answer is D 99 feet
