The speed of the yacht : 100 km/h
<h3>Further explanation </h3>
Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration
- At constant velocity motion:
the speed of vo = v = constant
acceleration = a = 0
Δx = vt or x = xo + vt
An equation of constant velocity motion
x = distance = m
v = speed = m / s
t = time = seconds
A yacht sailed at a steady speed for 0.5 hours, and traveled 50 kilometers
so the velocity/speed:
The total question is not found here but the onion structures that we can see with 30 X are the cell wall and an important vacuole.
<h3>What is 30X magnification?</h3>
The 30X magnification does not exist, nowadays the current objective lens comes in 20X, and 40X.
Using this magnification, we might see plant cells that divide to produce cell walls between daughter cells after a process called mitosis.
In conclusion, the total question is not found here but the onion structures that we can see with 30 X are the cell wall and an important vacuole.
Learn more about lens magnification here:
brainly.com/question/1599771
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Answer:
4777.09grams
Explanation:
To find the mass of oxygen, we first need to find the mass of potassium sulfate (K2SO4).
Since there are 4.50 x 10^25 formula units of potassium sulfate, we can find the number of moles in K2SO4 by dividing by Avagadros number (6.02 × 10^23 units). That is;
number of moles of K2SO4 (n) = 4.50 x 10^25 ÷ 6.02 × 10^23
= 0.747 × 10^ (25-23)
= 0.747 × 10^2
= 7.47 × 10^1 moles
Mass in grams of K2SO4 can be calculated thus: molar mass of K2SO4 × moles
= 174.252 g/mol × 7.47 × 10^1 moles
= 13016.62grams.
Since mass of oxygen in 1 mol of K2SO4 = O4 = 63.996 g/mol
We find the percentage by mass of oxygen in K2SO4 as follows:
= 63.996/174.252 × 100
= 0.367 × 100
= 36.7% by mass of oxygen.
This means that in 1gram of K2SO4, there are 0.367gram of Oxygen. Hence, in 13016.62grams (4.50 x 10^25 units) of K2SO4, there will be;
0.367 × 13016.62
= 4777.09grams of oxygen.