Answer:
Explanation:
Given:
A solution contains one or more of the following ions such as Ag, 
and 
Here the Lithium bromide is added to the solution and no precipitate forms
Solution:
Since with LiBr no precipitation takes place therefore Ag+ is absent
Here on adding 
to it precipitation takes place.
Precipitate is as follows,
Thus,
is present
When 
is added again precipitation takes place.
Therefore the reaction is as follows,
Therefore,
are present in the solution
Answer:
Q = 1379.4 J
Explanation:
Given data:
Mass of water = 22 g
Initial temperature = 18°C
Final temperature = 33°C
Heat absorbed = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water is 4.18 J/g.
°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 33°C - 18 °C
ΔT = 15°C
Q = 522 g ×4.18 J/g.°C× 15°C
Q = 1379.4 J
1.34*10^6
Move the decimal 6 times to the left, it is a number 1-10
Answer:
This is the answer of your question. ☺☺
Explanation:
Percentage composition of Cu is 71.54.
Percentage Composition of Br is 29.54.
