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makvit [3.9K]
3 years ago
8

Periodic Law Directed Reading

Chemistry
2 answers:
kolbaska11 [484]3 years ago
8 0

Answer:

C

Explanation:

spayn [35]3 years ago
4 0

Answer:Developed a method for organizing elements based on their atomic number

Explanation:

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Assume that the reaction of aqueous hydrobromic acid solution and potassium hydroxide base undergoes a complete neutralization r
Tamiku [17]

Answer:

a.

HBr + KOH → KBr + H  _{2} O

b.

1000 \: ml \: contains \: 0.685 \: moles \\ 55.4 \: ml \: contains \: ( \frac{55.4 \times 0.685}{1000} ) \\  = 0.038 \:moles \\ 1 \: mole \: of \: hydrobromic \: acid  \: produces \: 1 \: mole \: of \: water \\ 0.038 \: moles \: produce \: (0.038 \times 1) \\  = 0.038 \: moles \\ 1 \: mole \: of \: water \: weighs \: 18 \: g \\ 0.038 \: moles \: weighs \: (0.038 \times 18) \: g \\  = 0.684 \: g

c.

0.042 M

d.

1.4

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2 years ago
Which one is a true statement about endothermic reactions? a: More heat is given off than is put into the reaction. b :The react
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3 years ago
The atomic mass of Cu is 63.5. Find its electrochemical equivalent​
FrozenT [24]

Answer:

The electrochemical equivalent of copper, Cu, is 3.29015544 × 10⁻⁷ g/C

Explanation:

The given parameters are;

The element for which the electrochemical equivalent is sought = Copper

The atomic mass of copper = 63.5

The electrochemical equivalent, 'Z', of an element or a substance is the mass, 'm', of the element or substance deposited by one coulomb of electricity, which is equivalent to a 1 ampere current flowing for a period of 1 second

Mathematically, we have;

m = Z·I·t = Z·Q

We have;

Cu²⁺ (aq) + 2·e⁻ → Cu

Therefore, one mole of Cu, is deposited by 2 moles of electrons

The charge carried one mole of electrons = 1 Faraday = 96500 C

∴ The charge carried two moles of electrons, Q = 2 × 96500 C = 193,000 C

Given that the mass of an atom of Cu = 63.5 a.m.u., the mass of one mole of Cu, m = 63.5 g

Z = \dfrac{m}{Q} = \dfrac{63.5 \ g}{193,000 \ C} = 3.29015544 \times 10^{-4} \, g \cdot C^{-1}

∴ Z = 3.29015544 × 10⁻⁴ g/C = 3.29015544 × 10⁻⁷ g/C

The electrochemical equivalent of copper, Cu, is Z = 3.29015544 × 10⁻⁷ g/C

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3 years ago
]\ \textless \ br /\ \textgreater \ \huge \boxed{ \red{φµεรƭเσɳ -}} \ \textless \ br /\ \textgreater \ ​ \ \textless \ br /\ \te
azamat

Answer:

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