There are 2.71*10^24 atoms of oxygen.
1st) It is necessary to calculate the amount of oxygen in 1.50mol of sodium carbonate (Na2CO3).
We know that 1 mole of sodium carbonate has 3 moles of oxygen, so to calculate the moles of Oxygen in 1.50 moles of Na2CO3 we can use a mathematical Rule of Three:
Now we know that there are 4.5 moles of oxygen in 1.50 moles of sodium carbonate.
2nd) Finally, we can calculate the atoms of oxygen using the Avogadro's number (6.022*10^23 atoms/mol):
So, there are 2.71*10^24 atoms of oxygen in 1.50 mol of sodium carbonate.
Answer:
the same thing that happens to United states will happen to other regions
Explanation:
When we write a formula of a compound in its simplest form, it is empirical formula.
Given the molecular formula is = C₁₈H₃₆
Now we can relate both empirical and molecular formula as;
Molecular formula = n x empirical formula
C₁₈H₃₆ = 18 x CH₂
So the empirical formula of C₁₈H₃₆ is CH₂
Answer:
hm step by step try to figure it 9ut
The moles of I₂ will form from the decomposition of 3.58g of NI₃ is 0.0136 moles.
<h3>How we calculate moles?</h3>
Moles of any substance will be calculated as:
n = W/M, where
W = required mass
M = molar mass
Given chemical reaction is:
2NI₃ → N₂ + 3I₂
Moles of 3.58g of NI₃ will be calculated as:
n = 3.58g / 394. 71 g/mol = 0.009 moles
From the stoichiometry of the solution, it is clear that:
2 moles of NI₃ = produce 3 moles of I₂
0.009 moles of NI₃ = produce 3/2×0.009=0.0136 moles of I₂
Hence, option (3) is correct i.e. 0.0136 moles.
To know more about moles, visit the below link:
brainly.com/question/15303663
