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kap26 [50]
3 years ago
13

Read this description of the life cycle of a mushroom. 1. A mushroom begins to grow underground as a single-celled "spore.” 2. T

he spore grows into multicellular structures called "hyphae.” 3. The hyphae absorb nutrition and detect when conditions are right to sprout a mushroom above ground. 4. The sprouted mushroom then forms new spores that can enter the ground and begin the life cycle again. Which sentence about this life cycle shows that mushrooms need energy and respond to stimuli? A mushroom begins to grow underground as a single-celled “spore.” The spore grows into multicellular structures called “hyphae.” The hyphae absorb nutrition and detect when conditions are right to sprout a mushroom above ground. The sprouted mushroom then forms new spores that can enter the ground and begin the life cycle again.
Mathematics
1 answer:
Dahasolnce [82]3 years ago
4 0

The correct answer is C. The hyphae absorb nutrition and detect when conditions are right to sprout a mushroom above ground.

Explanation:

Two key features of living organisms are energy processing and response to stimuli. These two features imply organisms require nutrients, which can be taken from the environment or created through a process such as photosynthesis and they sense their surroundings and respond to it.

Moreover, these two features are exemplified by mushroom (fungi) in the sentence "The hyphae absorb nutrition and detect when conditions are right to sprout a mushroom above ground" because the first section shows the developing mushroom takes nutrients from the soil or its environment and this is essential for growing and survival. Also, the second section of the sentence shows the developing mushroom can sense its environment and respond by developing only in appropriate conditions.

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Can u all help me????
ira [324]

Answer:

No it doesn't because y has two 3's

Step-by-step explanation:

7 0
3 years ago
Lakeisha has 3 5/8 yards of fabric. She wants to make a dress that requires 2 1/2 yards of fabric. How much fabric will she have
mezya [45]

1/2 = 4/8

3 5/8 - 2 4/8 = 1 1/8 yards left over

4 0
3 years ago
Read 2 more answers
Consider the sequence 10, 2..
romanna [79]

Answer:  see below

<u>Step-by-step explanation:</u>

1) 10, 2, 1.2, 1.12, 1.112, 1.1112

t_n=\dfrac{t_{n-1}}{10}+1

t₁ = 10

t₂ = 10/10 + 1    = 2

t₃ = 2/10 + 1     = 1.2

t₄ = 1.2/10 + 1   = 1.12

t₅ = 1.12/10 + 1  = 1.112

t₆ = 1.112/10 + 1 = 1.1112

2)  10, 2, -2, -4, -5, -5.5, ...

t_n=\dfrac{t_{n-1}}{2}-3

t₁ = 10

t₂ = 10/2 - 3 =   2

t₃ = 2/2 - 3  =  -2

t₄ = -2/2 - 3 =  -4

t₅ = -4/2 - 3 =  -5

t₆ = -5/2 - 3 = -5.5

8 0
3 years ago
The population of a city in 2000 was 500,000 while the population of the suburbs of that city in 2000 was 700,000. Suppose that
Mnenie [13.5K]

Answer:

The population of the city in 2002 is 469,280 while the population of the suburb is 730,720.

Step-by-step explanation:

  • 6% of the city's population moves to the suburbs (and 94% stays in the city).
  • 2% of the suburban population moves to the city (and 98% remains in the suburbs).

The migration matrix is given as:

A= \left \begin{array}{cc}  \\ C \\S \end{array} \right\left[ \begin{array}{cc}  C&S\\ 0.94&0.06 \\0.02&0.98 \end{array} \right]

The population in the  year 2000 (initial state) is given as:

\left[ \begin{array}{cc}  C&S\\ 500,000&700,000  \end{array} \right]

Therefore, the population of the city and the suburb in 2002 (two years after) is:

S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\&  \end{array} \right\left \begin{array}{cc} \end{array} \right\left[ \begin{array}{cc} 0.94&0.06 \\0.02&0.98 \end{array} \right]^2

A^{2} = \left[ \begin{array}{cc} 0.8848 & 0.1152 \\\\ 0.0384 & 0.9616 \end{array} \right]

Therefore:

S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\&  \end{array} \right\left \begin{array}{cc} \end{array} \right \left[ \begin{array}{cc} 0.8848 & 0.1152 \\ 0.0384 & 0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 500,000*0.8848+700,000*0.0384& 500,000*0.1152 +700,000*0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 469280& 730720 \end{array} \right]

Therefore, the population of the city in 2002 is 469,280 while the population of the suburb is 730,720.

6 0
3 years ago
Suppose that the functions r and a are defined for all real numbers x as follows. r(x)=2x-1 S(x)=5x write the expressions for (r
NeTakaya

\boxed{(r-s)(x)=-3x-1} \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x} \\ \\ \boxed{(r+s)(-2)=-15}

<h2>Explanation:</h2>

In this exercise, we have the following functions:

r(x)=2x-1 \\ \\ s(x)=5x

And they are defined for all real numbers x. So we have to write the following expressions:

First expression:

(r-s)(x)

That is, we subtract s(x) from r(x):

(r-s)(x)=2x-1-5x \\ \\ Combine \ like \ terms: \\ \\ (r-s)(x)=(2x-5x)-1 \\ \\ \boxed{(r-s)(x)=-3x-1}

Second expression:

(r\cdot s)(x)

That is, we get the product of s(x) and r(x):

(r\cdot s)(x)=(2x-1)(5x) \\ \\ By \ distributive \ property: \\ \\ (r\cdot s)(x)=(2x)(5x)-(1)(5x) \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x}

Third expression:

Here we need to evaluate:

(r+s)(-2)

First of all, we find the sum of functions r(x) and s(x):

(r+s)(x)=2x-1+5x \\ \\ Combine \ like \ terms: \\ \\ (r+s)(x)=(2x+5x)-1 \\ \\ (r+s)(x)=7x-1

Finally, substituting x = -2:

(r+s)(-2)=7(-2)-1 \\ \\ (r+s)(-2)=-14-1 \\ \\ \boxed{(r+s)(-2)=-15}

<h2>Learn more: </h2>

Parabola: brainly.com/question/12178203

#LearnWithBrainly

5 0
3 years ago
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