First we define the varible to use:
x = represent the number of cookies
Cameron:
The amount of cookies he made was:
x
Deyonne:
We can rewrite the amount in different ways:
x + 0.25x
1.25x
Then, the total revenue is:
0.50 * (x + (x + 0.25x))
We rewrite:
0.50 * (x + 1.25x)
0.50 * (2.25x)
Answer:
The following expressions represent possible revenue from the sales:
F. 0.50 (2.25x
C. 0.50 (x + 1.25x)
A. 0.50 [x + (x + 0.25x)]
Answer:
do you have to add the numbers together or multiply
Answer:
{- 2, - 4, - 6, - 8, - 10 }
Step-by-step explanation:
Given
f(x) = 2x - 6 with domain { - 2, - 1, 0, 1, 2 }
To obtain the range substitute the values of x from the domain into f(x)
f(- 2) = 2(- 2) - 6 = - 4 - 6 = - 10
f(- 1) = 2(- 1) - 6 = - 2 - 6 = - 8
f(0) = 2(0) - 6 = 0 - 6 = - 6
f(1) = 2(1) - 6 = 2 - 6 = - 4
f(2) = 2(2) - 6 = 4 - 6 = - 2
Range is { - 2, - 4, - 6, - 8, - 10 }
Too lazy to format so here
R = 20D =
R = 20(6) =
120 = 20(6)
r = 120 = the days it cost to rent bike
so expensive
Complete question :
The GPAs of all students enrolled at a large university have an approximately normal distribution with a mean of 3.02 and a standard deviation of .29.Find the probability that the mean GPA of a random sample of 20 students selected from this university is 3.10 or higher.
Answer:
0.10868
Step-by-step explanation:
Given that :
Mean (m) = 3.02
Standard deviation (s) = 0.29
Sample size (n) = 20
Probability of 3.10 GPA or higher
P(x ≥ 3.10)
Applying the relation to obtain the standardized score (Z) :
Z = (x - m) / s /√n
Z = (3.10 - 3.02) / 0.29 / √20
Z = 0.08 / 0.0648459
Z = 1.2336940
p(Z ≥ 1.2336) = 0.10868 ( Z probability calculator)
