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erma4kov [3.2K]
3 years ago
15

A pound of swiss cheese costs $4.00 at the grocery store. Use the

Mathematics
1 answer:
amm18123 years ago
6 0

Answer:

3.

..2330

Step-by-step explanation:

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Tell whether the pair of polygons is similar. Explain why or why not. (3 points) I get the general idea of this but I’m having t
masha68 [24]

Answer:

PQRS and TUVW are similar.

Step-by-step explanation:

We are give two polygons.

Sides of first polygon are :

PQ = 8 ft

QR= 13ft

RS = 8ft

PS = 13ft.

Sides of second polygon:

TW = 2.4 ft

TU = 5.2 ft

UV = 2.4 ft

VW = 5.2 ft.

We can see that PQRS and TUVW are parallelograms.

Note: <em>If an angle of a parallelogram is equal to an angle of another parallelogram then parallelograms would be similar.</em>

We can see that <Q ≅ <T = 120°.

<h3>Therefore, PQRS and TUVW are similar.</h3>

5 0
2 years ago
Read 2 more answers
Add or Subtract to Simplify:<br> (4x - 2x3) + (5x3 - 4x + 5)
sukhopar [10]

Answer:

<h2>3x³ + 5</h2>

Step-by-step explanation:

( 4x - 2x³ ) + ( 5x³ - 4x + 5)

<u>Remove the parenthesis</u>

That's

4x - 2x³ + 5x³ - 4x + 5

<u>Group like terms</u>

We have

5x³ - 2x³ + 4x - 4x + 5

We have the final answer as

<h3>3x³ + 5</h3>

Hope this helps you

4 0
3 years ago
Help me with questions #1,3,4, &amp; 5
Klio2033 [76]
Q:3
Ans: 10.12 x 10 power -5
Q:4
Ans: 5/8
Q:5
Ans: - x cube and + x square  
7 0
3 years ago
Marcus is a member of a theater club. He pays a monthly fee and his movie tickets are then $5 for an unlimited number of movies
inn [45]
The monthly fee is 12.55=7.5$
4 0
2 years ago
Read 2 more answers
Line segment AB has a slope of 4/3 and contains point A (6,-5). What is the y-coordinate of point Q(2, y) if QA is perpendicular
timofeeve [1]

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope~of~AB}{\cfrac{4}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{4}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{4}}}\impliedby \textit{slope of QA} \\\\[-0.35em] ~\dotfill

\bf A(\stackrel{x_1}{6}~,~\stackrel{y_1}{-5})\qquad Q(\stackrel{x_2}{2}~,~\stackrel{y_2}{y}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{y-(-5)}{2-6}=\stackrel{\textit{QA's slope}}{-\cfrac{3}{4}}\implies \cfrac{y+5}{-4}=\cfrac{-3}{4} \\\\\\ 4y+20=12\implies 4y=-8\implies y=\cfrac{-8}{4}\implies \boxed{y=-2}

8 0
3 years ago
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