Answer:
(5,-4)
Step-by-step explanation:
If reflected over the x-axis, the quadrilateral would be in the fourth quadrant. N' would be at (1,-1) and P' at (6,-1). To reflect, look at the y-coordinate of the point and turn it to negative. With point Q, it's at (5,4) so we just flip the 4 to -4 and that's our point! (5,-4)
Answer:
P(≥ 7 males) = 0.0548
Step-by-step explanation:
This is a binomial probability distribution problem.
We are told that Before 1918;
P(male) = 40% = 0.4
P(female) = 60% = 0.6
n = 10
Thus;probability that 7 or more were male is;
P(≥ 7 males) = P(7) + P(8) + P(9) + P(10)
Now, binomial probability formula is;
P(x) = [n!/((n - x)! × x!)] × p^(x) × q^(n - x)
Now, p = 0.4 and q = 0.6.
Also, n = 10
Thus;
P(7) = [10!/((10 - 7)! × 7!)] × 0.4^(7) × 0.6^(10 - 7)
P(7) = 0.0425
P(8) = [10!/((10 - 8)! × 8!)] × 0.4^(8) × 0.6^(10 - 8)
P(8) = 0.0106
P(9) = [10!/((10 - 9)! × 9!)] × 0.4^(9) × 0.6^(10 - 9)
P(9) = 0.0016
P(10) = [10!/((10 - 10)! × 10!)] × 0.4^(10) × 0.6^(10 - 10)
P(10) = 0.0001
Thus;
P(≥ 7 males) = 0.0425 + 0.0106 + 0.0016 + 0.0001 = 0.0548
True. The midsegment of a triangle is halfway up the triangle, and since the top half and the full triangle are similar triangles, its dimensions are proportional.
This means half the height will give half the base (midsegment). So the midsegment is always half the length of the side it's parallel to.
Answer:So the number of outcomes with exactly 4 tails is 720/2/24 = 15. Finally we can now calculate the probability of getting exactly 4 tails in 6 coin tosses as 15/64 = 0.234 to 3 decimal places.
We need the values to answer this question
