Hey there!
Line passes through (4, -1) & is parallel to 2x -3y=9
Let's start off by identifying what our slope is. In the slope-intercept form y=mx+b, we know that "m" is our slope.
The given equation needs to be converted into slope-intercept form and we can do this by getting y onto its own side of the equal sign.
Start off by subtracting 2x from both sides.
-3y = -2x + 9
Then, divide both sides by -3.
y = (-2x + 9)/-3
Simplify.
y = 2/3x - 3
"M" is simply a place mat so if we look at our given line, the "m" value is 2/3. Therefore, our slope is 2/3.
We should also note that we're looking for a line that's parallel to the given one. This means that our new line has the same slope as our given line. Therefore, our new line has a slope of 2/3.
Now, we use point-slope form ( y-y₁=m(x-x₁) ) to complete our task of finding a line that passes through (4, -1). Our new slope is 2/3 & it passes through (4, -1).
y-y₁=m(x-x₁)
Let's start by plugging in 2/3 for m (our new slope), 4 for x1 and -1 for y1.
y - (-1) = 2/3(x - 4)
Simplify.
y + 1 = 2/3 + 8/3
Simplify by subtracting 1 from both sides.
y = 2/3x + 8/3 - 1
Simplify.
y = 2/3x + 5/3
~Hope I helped!~
-3(x-5)=45
distribute
-3x+15 = 45
subtract 15 from each side
-3x = 30
divide by -3
x = -10
Answer:
The first four terms of the above sequence are 1, 6, 11, 16.
Step-by-step explanation:
A sequence is defined by the function f(n)=f(n-1)+5.
Where n represents the number of the term for n>1
First Put n = 2
f(2)=f(2-1)+5.
= f (1) + 5
= -4 + 5
= 1
Second Put n = 3
f(3)=f(3-1)+5.
= f (2) + 5
= 1 + 5
= 6
Third Put n = 4
f(4)=f(4-1)+5.
= f (3) + 5
= 6+ 5
= 11
Second Put n = 5
f(5)=f(5-1)+5.
= f (4) + 5
= 11 + 5
= 16
Therefore the first four terms of the above sequence are 1, 6, 11, 16.
13-7 = 6 so that means 6 + 4 would make it ten
