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shutvik [7]
3 years ago
14

Perform the operation and reduce the answer fully. 3/10 - 3/30

Mathematics
1 answer:
barxatty [35]3 years ago
6 0

Answer:

1/5

Step-by-step explanation:

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Ronch [10]
The mode is 4,the median is 5 and mean 27
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2 years ago
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Find the area of the region bounded by the y-axis, the line y=6, and the line y = 1/2.
Ghella [55]

Solution:

As region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis.

We consider a line , one dimensional  if it's thickness is negligible.

So, Line is  two dimensional if it's thickness is not negligible becomes a quadrilateral.

So, Area (region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis)= Area of line segment between [,y=6 and  y=1/2.]= 6-1/2=11/2 units if we consider thickness of line as negligible.

4 0
3 years ago
-24 = -3w +21 what is w?
yuradex [85]

Answer:

w=15

Step-by-step explanation:

7 0
2 years ago
What is the product of and (6+5i) and (3-7i) ?<br><br> -17-27i<br> -17+27i<br> 53+27i<br> 53-27i
USPshnik [31]
We are going to make the product step by step.
 We have:
 (6 + 5i) * (3-7i)
 Multiplying:
 ((6) * (3)) + ((6) * (- 7i)) + ((5i) * (3)) + ((5i) * (- 7i))
 Rewriting:
 18 - 42i + 15i - 35i ^ 2
 18 - 42i + 15i - 35 * (- 1)
 18 - 42i + 15i + 35
 53 - 27i
 Answer:
 
the product of and (6 + 5i) and (3-7i) is:
 
53-27i
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3 years ago
Vineet solved a system of equations by substitution. In his work, he substituted an expression for one of the variables and solv
Eddi Din [679]

He can conclude that the system of equations has no solution since one equation in it always results with false equivalency.

Hope this helps.

r3t40

3 0
3 years ago
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