Which of the following could not be points on the unit circle?

Mathematics

2 answers:

enyata [817]3 years ago

5 0

Answer:

C and D

Step-by-step explanation:

NemiM [27]3 years ago

4 0

A. √(0.8^2) + (0.6^2) = √1 = 1 => OK

b.(-2/3,√ 5/3) = √(-2/3)^2 + 5/9) = √(4/9 +5/9) = √1 = 1 => OK

c.(√ 3/2, 1/3) = √(3/4 + 1/9) < 1 => it is inside the unit circle

d.(1,1) = √(1 + 1) = √2 > 1 => NO. This point is beyond the limits of the unit circle.

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Mashcka [7]

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LekaFEV [45]

Answer:

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Step-by-step explanation:

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Write the equation of a line that is perpendicular to y=7x−2 and passes through the point (14,8).(1 point) y=7x−90 y=10x−17 y=−1

True [87]

Answer:

$\huge\boxed{y=-\frac{1}{7}x+ 10}$

Step-by-step explanation:

In order to find the equation of this line, we need to note two things.

A) The slope of two lines that are perpendicular will be opposite reciprocals (that is, multiplying them gets us -1.)
B) We can substitute a point inside an incomplete equation to try and find a missing value.

So first, let's find the opposite reciprocal of 7 which will be the slope to this equation.