Answer:
The answer is "Option a"
Explanation:
A Sparkline is a small graph, which is available inside a sheet, that displays information visually. It displays the information is in the form of patterns on several values. It also uses underline to display the low and high value, use with sparklines, and certain alternatives were wrong, which can be defined as follows:
- In option b, It is used to define the overall view of data, that's why it is wrong.
- Option c and Option d both are wrong because, create command is used to create data, or view is used to show that data, they both don't use sparkline option.
Answer:
Forward the packet to the next hop router specified by the route network 0.0.0.0
Explanation:
Answer: True
Explanation:
Yes, the given statement is true that the due to the very low feasibility the IT (Information technology) department are not aware of the hidden backlog that basically contain projects.
The feasibility is the main factor in the IT department as it helps to study whole objective of the project and then also uncover all the strength and weakness of the project so that we can easily go through the details to make the project more efficient and reliable.
<span>Any computer or device on a network that can be addressed on the local network is referred to as a: node.</span>
Answer:
answer:
#include <iostream>
#include<list>
using namespace std;
bool Greater(int x) { return x>3; } int main() { list<int>l; /*Declare the list of integers*/ l.push_back(5); l.push_back(6); /*Insert 5 and 6 at the end of list*/ l.push_front(1); l.push_front(2); /*Insert 1 and 2 in front of the list*/ list<int>::iterator it = l.begin(); advance(it, 2); l.insert(it, 4); /*Insert 4 at position 3*/ for(list<int>::iterator i = l.begin();i != l.end();i++) cout<< *i << " "; /*Display the list*/ cout<<endl; l.erase(it); /*Delete the element 4 inserted at position 3*/ for(list<int>::iterator i = l.begin();i != l.end();i++) cout<< *i << " "; /*Display the list*/ cout<<endl;
l.remove_if(Greater); for(list<int>::iterator i = l.begin();i != l.end();i++) cout<< *i << " ";
/*Display the list*/
cout<<endl; return 0;
}
