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Nikolay [14]
3 years ago
15

A chemist mixes a 10% hydrogen peroxide solution with a 25% hydrogen peroxide solution to create 30 liters of a 15% hydrogen per

oxide solution. How many liters of the 10% solution did the chemist use to make the 15% solution?
Mathematics
2 answers:
kupik [55]3 years ago
6 0
The answer is 20 liters.
Alenkasestr [34]3 years ago
5 0

Answer:

the answer is 20 liters

Step-by-step explanation:

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How do i find the surface area of a cylinder with a radius of 3.5 ft. and a height of 14 ft.
Karolina [17]
The formula for the surface area of a cylinder is:
2<span>π</span><span>r</span><span>h </span><span>+ </span><span>2</span><span>π</span><span>r^</span><span>2

If we substitute in the measurements that we know, you get:

2</span><span>\pi (3.5) (14) + 2</span><span>\pi (3.5)^2

If we simplify this expression, we get:

98</span><span>\pi + 24.5</span><span>\pi

If you simplify once more, you get

122.5</span><span>\pi or </span><span>≈ 384.85

Therefore, the surface area is 122.5</span>\pi or about 384.85<span>


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3 0
3 years ago
Solve each system using substitution or elimination. Show all required work. X^2+y^2=40 -x+y=-8
mr_godi [17]

Answer:

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4 0
3 years ago
A colored chip is yellow on one side and red on the other. The chip was flipped 50 times and landed yellow side facing up 30 tim
Nat2105 [25]
60% 
50/30 is 0.6
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7 0
3 years ago
Read 2 more answers
X is the sum of y consecutive integers. w is the sum of z consecutive integers. If y = 2z, and y and z are both positive integer
zlopas [31]

Answer:

The answer is C.

Step-by-step explanation:

The key to solve the problem is the equation given

y = 2z         which means that<u> y is always an even number.</u>

For example:

let z = 1;       y  = 2(1)     y = 2;

let z = 2;      y  = 2(2)     y = 4;

let z = 3;      y  = 2(3)     y = 6;

And we know that for any set of consecutive integers with an even number of terms, the sum of the integers is never a multiple of the number of terms.

For example:

Set of numbers: [1,2,3,4,5,6] ;

Sum of the set:  1+2+3+4+5+6 = 21 ;

Number of terms of the set: 6;

Therefore, 21 is not a multiple of 6.

But for any set of consecutive integers with an odd number of terms, the sum of the integers is always a multiple of the number of terms.

For example:

Set of numbers: [1,2,3,4,5,] ;

Sum of the set:  1+2+3+4+5 = 15 ;

Number of terms of the set: 5;

Therefore, 15 is a multiple of 5.

And that's why we know that if y is always an even number (y = 2z), the sum of the consecutive integers (x) is not a multiple of y, therefore x/y cannot be an integer.

8 0
4 years ago
Please help! it’s not too hard but i am still confused.
IRISSAK [1]

The four integers you are looking for is 28,30,32 and 34.

5 0
3 years ago
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