Answer:
![\sqrt[4] {x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%20%7Bx%5E3%7D)
Step-by-step explanation:
At this point, we can transform the square root into a fourth root by squaring the argument, and bring into the other root:
![\sqrt x \cdot \sqrt[4] x =\sqrt [4] {x^2} \cdot \sqrt[4] x = \sqrt[4]{x^2\cdot x} = \sqrt[4] {x^3}](https://tex.z-dn.net/?f=%5Csqrt%20x%20%5Ccdot%20%5Csqrt%5B4%5D%20x%20%3D%5Csqrt%20%5B4%5D%20%7Bx%5E2%7D%20%5Ccdot%20%5Csqrt%5B4%5D%20x%20%3D%20%5Csqrt%5B4%5D%7Bx%5E2%5Ccdot%20x%7D%20%3D%20%5Csqrt%5B4%5D%20%7Bx%5E3%7D)
Alternatively, if you're allowed to use rational exponents, we can convert everything:
![\sqrt x \cdot \sqrt[4] x = x^{\frac12} \cdot x^\frac14 = x^{\frac12 +\frac14}= x^{\frac24 +\frac14}= x^\frac34 = \sqrt[4] {x^3}](https://tex.z-dn.net/?f=%5Csqrt%20x%20%5Ccdot%20%5Csqrt%5B4%5D%20x%20%3D%20x%5E%7B%5Cfrac12%7D%20%5Ccdot%20x%5E%5Cfrac14%20%3D%20x%5E%7B%5Cfrac12%20%2B%5Cfrac14%7D%3D%20x%5E%7B%5Cfrac24%20%2B%5Cfrac14%7D%3D%20x%5E%5Cfrac34%20%3D%20%5Csqrt%5B4%5D%20%7Bx%5E3%7D)
9514 1404 393
Answer:
A: 66/21
E: 22/7
Step-by-step explanation:
The offered choices reduce to 3 1/7 or to 3. The best approximations of those given are the ones that reduce to 3 1/7.
A: 66/21 = 22/7 = 3 1/7
B: 60/20 = 3
C: 21/7 = 3
D: 45/15 = 3
E: 22/7 = 3 1/7
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<em>Comment on pi approximations</em>
The ratio 22/7 differs from π by about 0.04%. A better approximation is 355/113, which differs from π by about 0.000008%. The approximation 3.14 differs from π by about 0.05%.
It would most likely be 41 because when you would round 41 after you would × 41 times 10 equals 410 then you would round it to 400
<u><em>The answer:</em></u> 6x^3+18x
<u><em>The Explanation:</em></u> You need to uses distributive property to 6x to x^2+3 which will be 6x^3+18x
Answer:
70
Step-by-step explanation:
We have the final part 4x/40 = 7. We can simplify this to x/10 = 7 by dividing the numerator and the denominator by 4. We then multiply both sides by 10 to get x = 70
