I am assuming you wrote the problem wrong. Is it a^2?
A^2 -4A-21=0
(A-7)(A+3)=0
A=7 A=-3, ignore the negative number because it doesn't make sense if you plug in for a.
length=a+3=7+3=10
Width=7=a
Answer:
x+12=12(opposite sides of parallelogram are equal)
x=0
<em><u>Option B</u></em>
The result of addition is 2y = 24
<em><u>Solution:</u></em>
Given that we have to add the equations
<em><u>Given equations are:</u></em>
5x - y = -1
-5x + 3y = 25
We have to add both equations
This is similar to adding numbers. i,e 1 + 2 = 3
<em><u>For adding variables,</u></em>
When adding or subtracting terms that have exactly the same variables, you either add or subtract the coefficients, and let the result stand with the variable.
Example: 2x + 3x = 5x
Keeping this in mind, let us add the given equations
5x - y = -1
-5x + 3y = 25
----------------------------
0 + 2y = -1 + 25
[ 5x and -5x cancels each other. Combine -y and 3y which gives 2y]
2y = 24
Thus Option B is correct
Answer:
15
because five times three is fifteen
Answer:
![\frac{19}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B19%7D%7B4%7D)
Step-by-step explanation:
Multiply the whole number by the denominator.
![4*4 = 16](https://tex.z-dn.net/?f=4%2A4%20%3D%2016)
Add the numerator (3) to 16.
![16 + 3 = 19](https://tex.z-dn.net/?f=16%20%2B%203%20%3D%2019)
19 will be our new numerator for the improper fraction. The original denominator (4) stays the same.
![4\frac{3}{4} = \frac{19}{4}](https://tex.z-dn.net/?f=4%5Cfrac%7B3%7D%7B4%7D%20%3D%20%5Cfrac%7B19%7D%7B4%7D)