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creativ13 [48]
3 years ago
6

How to solve for B in this equation: A= 3B + 7C

Mathematics
1 answer:
Katen [24]3 years ago
6 0

Answer:

(A -7C)/3 = B

Step-by-step explanation:

A= 3B + 7C

We want to get B isolated

Subtract 7C from each side

A-7C= 3B + 7C-7C

A -7C = 3B

Divide by 3 on each side

(A -7C)/3 = 3B/3

(A -7C)/3 = B

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3 years ago
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can someone j help me w this, ive reposted it twice now :-(((( due in an hour please help!:( will give brainliest
Doss [256]

Step-by-step explanation:

I got you,

a) Work...

First equation: y = 4x + 3

Second equation: y = 2x + 11

If he wants to play 2 games...

y = 4 (2) + 3

y = 11

y = 2 (2) + 11

y = 15

<u>Answer for part a: If a customer wants to rent shoes and play two games, they'll pay more with the new price plan. With the current price plan, they'll pay 11 dollars, but with the new price plan, they'll pay 15 dollars.</u>

b) Work...

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y = 4 (7) + 3

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y = 25

<u>Answer for part b: If the customer wants to play 7 games, including the shoes, they would pay less using the new plan. If the shes were not included, the new price will still be less. With the shoes, 7 games, with the original plan, is 31 dollars but 25 dollars with the new plan. If they didn't want to rent shoes, they would pay 28 dollars with the original plan but only 14 dollars with the new plan. All in all, they spend less on the new plan anyways.</u>

I hope this helps :)

7 0
3 years ago
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When a researcher asks respondents for the names or identities of others like themselves who might qualify to take part in the s
DanielleElmas [232]

Answer:

Chain referral sampling

Step-by-step explanation:

Chain referral sampling is also known as snowball sampling. In this form of sampling, the samples are collected from the referrals given by the existing samples. The samples are collected and the research is conducted respectively. This method is used in the business marketing also. The places where the people are not known by the company, the method of chain referrals are made and the samples are collected.

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Dennis_Churaev [7]
0.632

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