The perimeter of a rectangular floor is 50 feet. find the dimensions of the floor if the length is four times the width.

Mathematics

1 answer:

lapo4ka [179]3 years ago

3 0

Length is 20
width is 5

let me know if you need more details

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Without further study, you forget things as time passes. A model of human memory gives the percentage, p, of acquired knowledge

PIT_PIT [208]

Answer:

42.69% of information is acquired by the student in two weeks.

Step-by-step explanation:

We are given the following in the question:

$p = (100 -a)e^{-bt} + a$

where a and b are constants.

$a = 18\\b = 0.6$

p tells us about the percentage of acquired knowledge that a person retains after t weeks.

We have to find the percentage of knowledge acquired in two week.

We put t = 2

$p = (100 -18)e^{-(0.6)(2)} + 18\\p = 42.69$

Thus, 42.69% of information is acquired by the student in two weeks.

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3 years ago

Which set of coefficients of the terms in the expansion of the binomial (x+y)^3 is correct ?

BigorU [14]

We are technically FOILing this out... with a power of 3.

(x+y)(x+y)(x+y)

So we can first factor out the first two "x+y"s.

$( x^{2} +2xy + y^{2} )$ , multiplied by the last "x+y".

$x^{3} +3 x^{2} y +3x y^{2} + y^{3}$

Coefficients are the number that comes in front of a variable.

In this case, 1 comes in front of $x^{3}$ , 3 comes in front of $x^{2} y$ , 3 comes in front of $x y^{2}$ , and 1 comes in front of $y^{3}$ .

Thus: 1, 3, 3, 1.
Answer Choice A

4 0

3 years ago

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A polynomial has a leading coefficient of 1 and the

Hoochie [10]

Answer:

(A) $[x-(2+i)][x-(2-i)][x-\sqrt{2}][x+\sqrt{2}]$

Step-by-step explanation:

A polynomial has a leading coefficient of 1 and the following factors with multiplicity 1:

$x-(2+i)\\x-\sqrt{2}$

We apply the following to find the factored form of the polynomial.

If a complex number is a root of a polynomial with real coefficients, its complex conjugate is also a root of that polynomial.

If the polynomial has an irrational root $a+\sqrt{b}$ , where a and b are rational and b is not a perfect square, then it has also a conjugate root $a-\sqrt{b}$ .